Let
x = Mike age
x - 6 = Gabe age
92 = combined age
- - - - - - - - - - - - - - - - - - - - - - - - - - -
X + x - 6 = 92
2x - 6 = 92
2x - 6 + 6 = 92 + 6
2x = 98
2x/2 = 98/2
x = 49
The answer is x = 49
Insert the x value into the equation
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
x + x - 6 = 92
49 + 49 - 6
49 + 43 = 92
92 = 92
- - - - - - - - - - - - - - - - - - - - - - - - - - -
Gabe age is 43
Mike age is 49
2006-10-11 05:49:43
·
answer #1
·
answered by SAMUEL D 7
·
0⤊
0⤋
Hi,
Gabe + 6 = Mike
Gabe + Mike = 92
Gabe + (Gabe + 6) = 92
2 Gabe = 92- 6
2 Gabe = 86
Gabe = 43
Gabe is 43 years old.
:-)
2006-10-11 11:45:21
·
answer #2
·
answered by Anonymous
·
1⤊
0⤋
[1] G+6 = M
[2] G + M = 92
[3] (From 1) G = M-6
[4] (From 2) G = 92-M
[5] (Taking 4 from 3) M-6 = 92-M
[6] (Re-arrange 5) 2M = 98
Therefore M = 49
[7] (Substitute M = 49 into 1) G+6 = 49
Re-arranging 7 you get G =43
Therefore Gabe is 43, Mike is 49
2006-10-11 12:21:00
·
answer #3
·
answered by Robbo31 3
·
0⤊
0⤋
Gabe is 43
2006-10-11 12:08:52
·
answer #4
·
answered by william_mac_13 2
·
0⤊
0⤋
Let gabe's age=x
Mike's age=x+6
x+x+6=92
2x=86
x=Gabe's age=43
Mike's age=49
Sum=92 verified
ok
2006-10-11 11:46:10
·
answer #5
·
answered by openpsychy 6
·
1⤊
0⤋
Divide 92 by 2 = 46
Subtract 3 from 46
Add 3 to the other 46
43 and 49
2006-10-11 11:48:52
·
answer #6
·
answered by davebarrca 4
·
0⤊
0⤋
G + 6 = M
G + M = 92
G + (G+6) = 92
2G + 6 = 92
2G = 92-6 = 86
G = 86/2 = 43
M = G + 6 = 43 + 6 = 49
2006-10-11 11:45:12
·
answer #7
·
answered by Grant d 4
·
1⤊
0⤋
G = M - 6
G + M = 92
(M-6) + M = 92
2M - 6 = 92
2M = 84
M = 42
so, if mike is 42, gabe is 50.
2006-10-11 11:48:30
·
answer #8
·
answered by smartee 4
·
0⤊
0⤋
This isn't an age old question, it's year 9 simultaneous equations problem.
Remember back when you were 14!
G=M-6
G+M=92
=>2M=98
=>M=49
=G=43
Gabe is 43
2006-10-11 11:46:31
·
answer #9
·
answered by Stuart T 3
·
0⤊
0⤋
43
2006-10-11 11:44:18
·
answer #10
·
answered by Ricky Lee 6
·
0⤊
1⤋