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Erm take the rope to be massless. Am confused by the physics of springs and ropes.. arghh!

2006-10-11 03:08:35 · 4 answers · asked by Anonymous in Science & Mathematics Physics

4 answers

The tension in the rope would be expressed in terms of force, therefore would be F (as in 1F). Since the forces are opposing, the answer is achieved by simply subtracting.

2006-10-11 03:14:27 · answer #1 · answered by finaldx 7 · 0 0

I'm trying to imagine a real life situation where this might be even remotely possible, and the best one I came up with is a rocket traveling to outerspace, where the rocket is your rope.

It would have to be a rather unique rocket however, with the engine pulling from up front instead of pushing... :-)

Ok, the engine is pulling along with a force of 2F, however there is some atmospheric and gravitational drag involved, essentially pulling from the other end with a force of 1F.

The amount of linear stress on the rope/rocket would be 1F - the LESSER of the two opposing forces... However, that would only be true for a short particular instant - or if you assume (incorrectly) that the forces somehow remain constant, regardless of accelleration and speed.

You did say the rope has no mass. If it did, then at the very instant, the start of applying the opposing forces, the total stress would CUMULATIVE (3F), and decrease towards 1F as movement and momentum began to develop.

Duh.... a simpler analogy would have been a game of tug-of-war, but not quite so exciting. :-)

2006-10-11 11:05:34 · answer #2 · answered by M Hirsch 2 · 0 0

You have to specify how the rope is held.Suppose the rope is free to move. Then there will be no tension in the rope and acted upon by the resultant force of F it will move and in fact accelerate. Suppose the rope is constrained and it can not move. Then the resultant force acting on the force shall be F balanced by rope tension of F. So the tension in the rope shall be F

2006-10-11 10:15:49 · answer #3 · answered by openpsychy 6 · 0 0

the tension in the rope is in the opposite direction to the force of 2F and hear we can say that the tensionis in the rope is the force oppossing the greater force that is F and u shoud not confuse in the rope and spring caus in the spring we are using F= -kx and the kinetic energy is K= 1/2kx^2,where x is distance and K is constant.

2006-10-11 10:42:59 · answer #4 · answered by opthalmic 1 · 0 0

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