2006-10-11 01:02:26 · 10 answers · asked by pooh 1 in Science & Mathematics ➔ Mathematics
Either n = 0, or n - 11 = 0 <=> n = 11. So you have two solutions.
2006-10-11 01:07:01 · answer #1 · answered by Dimos F 4 · 0⤊ 1⤋
24n = 0 (Divide both sides by 24)
n = 0
n - 11 = 0 (Add 11 to both sides)
n = 11
Therefore, n= 0 or n = 11
QED
2006-10-11 09:13:50 · answer #2 · answered by CSUFGrad2006 5 · 0⤊ 0⤋
24n(n-11)=0
so,
either 24n=0 or n-11=0
If 24n=0, n=0
If n-11=0, n=11
2006-10-11 02:10:07 · answer #3 · answered by alien 1 · 0⤊ 0⤋
when the product of 2 numbers are equal to 0, then both the numbers individually are equal to 0. so,
24n=0
=>n=0
n-11=0
=>n=11
so you have 2 solutions. n=0,11
2006-10-11 01:28:02 · answer #4 · answered by 123 2 · 0⤊ 0⤋
24n(n-11)=0
24n=0 or n-11=0
n=0 or n=11
2006-10-11 03:00:49 · answer #5 · answered by . 3 · 0⤊ 0⤋
24n(n-11)=0
n=0 or
n-11=0; n=11
2006-10-14 15:03:16 · answer #6 · answered by yupchagee 7 · 0⤊ 0⤋
24n=0,n-11=0
n=0,11
:)
2006-10-11 01:07:57 · answer #7 · answered by shru189 1 · 0⤊ 0⤋
n = 0 and n = 11
why you ask?
24(0)((0)-11) = 0
and
24(11)((11)-11) = 0
2006-10-11 01:13:27 · answer #8 · answered by Anonymous · 0⤊ 0⤋
24n(n-11)=0
24n*-264n=0
24n*=264n
24n*/264n=264n/264n
1/24n
n=-1/24
2006-10-15 00:45:04 · answer #9 · answered by mich 2 · 0⤊ 0⤋
Please check this link to know how to solve quad equations
2006-10-11 01:40:27 · answer #10 · answered by Max Z 2 · 0⤊ 0⤋