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and then write them as ionic equations:

1. KBr(aq) + AgNO3(aq) > KNO3(aq) + AgBr(s)

2. HCl(aq) + KOH(aq) > KCl(aq) + H2O(l)

3. Pb(NO3)2(aq) + NaCl(aq) > PbCl2(s) + NaNO3(aq)

4. H2SO4(aq) + NaOH(aq) > Na2SO4(aq) + H2O(l)

5. HNO3(aq) + Mg(OH)2(aq) > Mg(NO3)2(aq) + H2O(l)


If anyone has the first clue about how to do this then please please help me. I've read so many books on doing this but I just don't get it at all. I know the first two equations are already balanced, I just don't have a clue about cancelling out the spectators etc and writting the ionic bit properly.

This is for an assignment so I have to get it right lol.

Any help much appreciated. Thanks.

2006-10-11 00:35:02 · 3 answers · asked by yummygummybear2006 1 in Science & Mathematics Chemistry

3 answers

1. Already balanced.

Br-(aq) + Ag+(aq) -> AgBr(s)

2. It's ballanced.

H+(aq) + OH-(aq) -> H2O(l) or H3O+(aq) + OH-(aq) -> 2H2O(l)

3. Pb(NO3)2(aq) + 2NaCl(aq) -> PbCl2(s) + 2NaNO3(aq)

Pb2+(aq) + 2Cl-(aq) -> PbCl2(s)

4. H2SO4(aq) + 2NaOH(aq) -> Na2SO4(aq) + 2H2O(l)

H+(aq) + OH-(aq) -> H2O(l) or H3O+(aq) + OH-(aq) -> 2H2O(l)

5. 2HNO3(aq) + Mg(OH)2(aq) -> Mg(NO3)2(aq) + 2H2O(l)

H+(aq) + OH-(aq) -> H2O(l) or H3O+(aq) + OH-(aq) -> 2H2O(l)

2006-10-11 01:02:09 · answer #1 · answered by Dimos F 4 · 0 0

3. Pb(NO3)2(aq) + 2NaCl(aq) > PbCl2(s) + 2NaNO3(aq)

4. H2SO4(aq) + 2NaOH(aq) > Na2SO4(aq) + 2H2O(l)

5. 2HNO3(aq) + Mg(OH)2(aq) > Mg(NO3)2(aq) + 2H2O(l)

Just make sure that there are the same number of atoms on each side of the equation. Don't let the formulae fool you - you can even write then down the page to check, just make sure when you are adding more of a chemical you add the whole molecule!

2006-10-11 01:01:55 · answer #2 · answered by advent m 3 · 0 0

1. & 2. Already balanced.


3. Pb(NO3)2 + 2NaCl -> PbCl2 + 2NaNO3

4. H2SO4+ 2NaOH -> Na2SO4 + 2H2O

5. 2HNO3(aq) + Mg(OH)2(aq) -> Mg(NO3)2(aq) + 2H2O(l)

2006-10-11 02:53:16 · answer #3 · answered by im4friend 2 · 0 0

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