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This clock has a regular hexagon face. The sum of the numbers along the top side is 24, that is 11+12+1. Rearrange the numbers on the clock so that the sum of the three numbers along any side is 17. Hard? If you got the answer shout it out heh..Let's see how smart you are to work this puzzle^-^

2006-10-10 23:51:01 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

the thing is that some (6 to be exact) are shared by two sides so that it is really workable.


Start at a corner with one and go clockwise

1, 9, 7 , 4, 6, 8, 3 ,12, 2, 10, 5, 11 and back to 1

Also check out a much tougher one at
http://www.geocities.com/~harveyh/unusustr.htm#Hexagram%20-%20magic%20triangles

2006-10-11 02:20:23 · answer #1 · answered by blind_chameleon 5 · 0 0

1

2017-01-18 13:43:45 · answer #2 · answered by Anonymous · 0 0

okay the only thing i came up with is a hexagon has six sides...you cant fit 3 number in each side...that would mean you would have 18 numbers inside...you will only get to use 2 numbers for each side...so i dont know the real answer to this question. even if you have 2 numbers for each side you still will not be able to equal 17...but if there is a correct answer let me know...i would like to see that conclusion

2006-10-11 00:37:03 · answer #3 · answered by mschwertner69 2 · 0 0

basically as a hexagon you will have 6 numbers at each vertice and 6 in the middle of each side.

This means 6 numbers get counted twice in different equations (the ones on the vertices).

Now to go and work it out :) I may be back in a bit.

2006-10-11 02:07:31 · answer #4 · answered by Tom J 1 · 0 0

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