integral volumes?

Question

Find the volume of the solid formed by rotating the region enclosed by
y=e^{1 x} + 2, y=0, x=0, x=0.8
about the x-axis.

Answer 1

Integrate pi ( TT) ( e^x + 2)^2 with respect to x, upper limit 0.8 lower limit 0.

= TT ( e^1.6 + 2e^0.8 + 4(0.8) ) - TT ( e^0 + 2e^0 + 4(0))
= 30.1722 cubic units

Answer 2

dV = π(e^x + 2)^2 dx
V = π(e^2x +4e^x + 4)dx
V = π((e^2x)/2 +4e^x + 4x) |x=0 to x=0.8
V = π((e^1.6)/2 - 1/2 +4e^0.8 - 4 +3.2)
V = 31.663