12x^2 - 25x + 12 = 0
solve for x
2006-10-10 17:29:21 · 3 answers · asked by aerojanie 1 in Education & Reference ➔ Homework Help
Method 1:
12x^2 - 25x + 12 = 0
(4x - 3)(3x - 4) = 0
4x-3=0 or 3x-4=0
x = 4/3 or 3/4
Method 2:
Quadratic formula:
a = 12, b = -25, c = 12
x = [-b +/- SqRt(b^2 - 4ac)] / 2a
= [25 +/- SqRt(625 - 576)] / 24
= (25 +/- 7) / 24
x = 32/24 or 18/24
x = 4/3 or 3/4
2006-10-10 17:30:43 · answer #1 · answered by PJ 3 · 0⤊ 0⤋
12x^2 - 25x +12 = 0
(4x - 3) (3x - 4) - 0
4x=3 , 3x = 4
x=3/4 , x= 4/3
2006-10-10 17:43:25 · answer #2 · answered by KVC 3 · 0⤊ 0⤋
not accustomed to English mathametical words, yet it is how I sparkling up it: 12x2 + x - 6 =0 D= a million + 288 = 289 (-a million + [sq. root of 289, that's 17] ) / 24 = 2/3 (-a million - [sq. root of 289, that's 17] ) / 24 = -3/4
2016-11-27 20:46:55 · answer #3 · answered by thweatt 4 · 0⤊ 0⤋