2006-10-10 17:02:43 · 15 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
it is prime. try to divide by all prime numbers < sqrt(43) or <=6 and see that there is a remainder.
2006-10-10 17:06:48 · answer #1 · answered by Mein Hoon Na 7 · 0⤊ 0⤋
41 43 47
Its Prime
2006-10-10 19:52:08 · answer #2 · answered by Sherman81 6 · 0⤊ 0⤋
43 is a Prime number
2006-10-10 17:14:53 · answer #3 · answered by aazib_1 3 · 0⤊ 0⤋
a prime number is the which can not be divided by a number other thar the number itself and 1 to get an integer
in case of 43 you start dividing
43/2=fraction(not an integer)
43/3=fraction(not an integer)
43/5=fraction(not an integer)
43/7=fraction(not an integer)
43/11=fraction(not an integer)
43/13=fraction(not an integer)
43/17=fraction(not an integer)
43/19=fraction(not an integer)
while applying this procedure only divide by prime numbers
2006-10-10 18:42:11 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Prime
2006-10-10 17:04:16 · answer #5 · answered by jack 6 · 0⤊ 0⤋
Prime. Its only factors are 43*1.
2006-10-14 14:46:19 · answer #6 · answered by yupchagee 7 · 0⤊ 0⤋
A composite number is a positive integer which has a positive divisor other than one or itself.
A prime number is a natural number that has exactly two (distinct) natural number divisors, which are 1 and the prime number itself.
43 has no positive divisor other than 1 and itself so it is a prime number.
2006-10-10 17:07:55 · answer #7 · answered by fsm 3 · 0⤊ 0⤋
It is prime, that is, undivisible by any numbers other than 1 and itself (43)
2006-10-10 18:00:06 · answer #8 · answered by indian_gogirl 2 · 0⤊ 0⤋
its prime number
2006-10-10 17:29:10 · answer #9 · answered by sameer 2 · 0⤊ 0⤋
It's not even, so you can't divide it by 2,4,or 6
sum-of-digits = 7, so it's not divisible by 3
It doesn't end in 5, so it's not divisible by 5.
7*6 = 42
7 > sqrt(42), so you've covered all the possibilities
It can't be factored, so it must be prime.
2006-10-10 17:12:00 · answer #10 · answered by Helmut 7 · 0⤊ 0⤋