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find the interest rate r for an investment of $1200 that earned $66 in interest for one year

2006-10-10 16:19:22 · 5 answers · asked by NABEELiOS 1 in Science & Mathematics Mathematics

5 answers

i=prt
t=1
p=1200
i=66
66=1200*r*1
66=1200r
r=66/1200=.055=5.5%

2006-10-10 16:26:39 · answer #1 · answered by yupchagee 7 · 16 0

Remember the formula- Principle * (interest)^(rate * time)

1200(1 + r)^(1) = 1266
1 + r = 1266/1200
r = 66/1200

2006-10-10 23:23:40 · answer #2 · answered by Skop 2 · 0 0

x = 66 x 100% ; x =6600/1200; x = 5,5%

2006-10-10 23:55:52 · answer #3 · answered by Freesia 5 · 0 0

s=prt
t=1
p=1200
s=66
66=1200*r*1
66=1200r
r=66/1200=.055=5.5%

2006-10-11 01:22:29 · answer #4 · answered by sameer 2 · 0 0

5.5%.

1200x=66

66/1200

2006-10-10 23:22:40 · answer #5 · answered by Anonymous · 0 0

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