This is an equation in two variables x and y, so one needs two equations to solve for x or y. However, x can be expressed in terms of y as follows:
y = (n / a)(a + x)
y = (n / a)a + (n / a)x
y = n + nx / a
ay = na + nx
nx + na = ay
nx = ay - na
x = (ay / n) - a
2006-10-10 16:28:22
·
answer #1
·
answered by fsm 3
·
0⤊
0⤋
Take n/a to the left hand side and that gives you
y (a/n) = a+x
as we want x, subtract eithersides by a
ya/n - a = x
simplify,
x = a(y/n - 1)
2006-10-10 16:24:23
·
answer #2
·
answered by cosmoboyin 2
·
0⤊
0⤋
Some of these are correct. Be certain to follow the order of operations. Otherwise, it will look correct and still be wrong.
2006-10-10 16:30:52
·
answer #3
·
answered by Jack 7
·
0⤊
0⤋
first, multiply both sides by 'a/n'. You get:
y*(a/n) = a+x
Then subtract right side by 'a' and isolate x.
Therefore, x = y*(a/n) - a
Hope this helps
2006-10-10 16:16:43
·
answer #4
·
answered by JSAM 5
·
0⤊
0⤋
y = (n/a)(a + x) multiply each side by a/n
ay/n=a+x subtract a from each side
ay/n-a=x so
x=ay/n-a=a(y/n-1)
2006-10-10 16:25:09
·
answer #5
·
answered by yupchagee 7
·
0⤊
0⤋
y = (n/a)(a + x)
We first distribute n/a to the (a + x)
y = (n/a)(a) + (n/a)(x)
We simplify
y = n + (n/a)x
We transpose n
y - n = (n/a)x
Now we reverse the equation
(n/a) x = y - n
Now we multiply (a/n) to both sides
(a/n)(n/a) x = (a/n)(y - n)
Thus,
x = (a/n)(y - n)
^_^
2006-10-11 00:50:51
·
answer #6
·
answered by kevin! 5
·
0⤊
0⤋
multiply both sides by (a/n)
(a/n)y = (a/n)(n/a)(a+x)
a/n and n/a cancel
ay/n = a+x
subtract a from both sides
ay/n - a = x
2006-10-10 16:19:55
·
answer #7
·
answered by Skop 2
·
2⤊
0⤋
y = (n/a)(a + x)
rearrange them and you will get
(n/a)(a + x) = y
n(a+x) = ay
a + x = (ay)/n
x = (ay)/n - a
x = (ay - an) / n
x = a (y - n) / n
2006-10-10 16:21:01
·
answer #8
·
answered by Mr. Logic 3
·
1⤊
1⤋
y = (n/a)(a + x)
a+x = y/(n/a)
x = y/(n/a) - a
2006-10-10 16:19:03
·
answer #9
·
answered by DanE 7
·
0⤊
0⤋
y=(n/a)(a+x)
y=(na/a)+(nx/a)
y=(na+nx)/a
y=[n(a+x)]/a
ya=n(a+x)
(ya)/n=a+x
[(ya)/n]-a=x
2006-10-10 16:21:08
·
answer #10
·
answered by Sheila 3
·
0⤊
0⤋