Who to start for week 6...
Delhomme (@ BAL) or A. Smith (vs SD)?
2006-10-10 16:05:18 · 11 answers · asked by apknuke 2 in Sports ➔ Fantasy Sports
You're in a tough situation with both QB's up against two real good defenses. I would go with Delhomme just because he has a more proven track record overall.
2006-10-10 16:13:17 · answer #1 · answered by frenchy62 7 · 0⤊ 0⤋
Delhomme
2006-10-10 18:56:15 · answer #2 · answered by Rusty Shackleford 5 · 0⤊ 0⤋
Ouch. Looks like you got youself in quite a mess with both quarterbacks starting against the Number 1 and 2 defenses. I would definitly go with Delhomme if i had to choose one, only becaue of his experience in the league and hes a better QB. Alex Smith is undependable too. He never/will never live up to the expectations from being drafted Number 1 in the NFL Draft.
2006-10-10 16:09:14 · answer #3 · answered by ijis d 2 · 0⤊ 0⤋
Delhomme, with better receivers and a weak running game I think they will be playing through the air to move the ball and that equals fantasy points for you!
2006-10-10 16:25:26 · answer #4 · answered by Chino 3 · 0⤊ 0⤋
both are playing tough defensives of the 2 Delhomme
2006-10-13 22:43:04 · answer #5 · answered by Anonymous · 0⤊ 0⤋
Delhomme is my fav QB both D's r tough but go with Delhomme . If u can pick up Pennington, Gradkoski, Leftwitch or Leinart. all 4 r better options this week. dont pick up harington against the jets Kerry Rhodes will eat him up
2006-10-10 16:11:06 · answer #6 · answered by K-Dog 3 · 0⤊ 0⤋
Both are playing tough defenses. Agh.
Look and see if Gradkowski is available. He's hot right now. If not, and you can't find a suitable replacement, go with Delhomme, he has more options and is more experienced. He also has a defense to back him up.
2006-10-10 16:07:52 · answer #7 · answered by ? 5 · 0⤊ 0⤋
Delhomme is a better pick.
2006-10-10 16:08:48 · answer #8 · answered by Agent A 2 · 0⤊ 0⤋
Delhomme (@ BAL)
2006-10-10 20:54:43 · answer #9 · answered by bigtime 4 · 0⤊ 0⤋
delhomme
2006-10-14 05:12:52 · answer #10 · answered by Brad C 2 · 0⤊ 0⤋