Rework problem 13 in section 4.1 of your text, involving drawing three cards from a deck of cards. Assume that the deck contains 4 aces, 7 other face cards, and 9 non-face cards, and that you randomly draw 3 cards. A random variable Z is defined to be 3 times the number of aces plus 2 times the number of other face cards drawn.
How many different values are possible for the random variable Z?
PART 2:
Fill in the table below to complete the probability density function. Be certain to list the values of Z in ascending order.
part 1 is 9 and the values are 1-9. i have no idea how to find the prob of 1-9 though
2006-10-10 15:30:18 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
There are finite combinations of Aces, face cards, and non facecards, so just calculate the value in each case.
To get the PDF, note that the size of the sample space is 20 choose 3 (20!/(3!17!)), then figure out the number of ways you can create each value of Z. The PDF is the latter value over the former.
2006-10-10 16:35:47 · answer #1 · answered by Fudge 2 · 0⤊ 0⤋
hated this stuff in school, still hate it and it's my supper time, sorry... just write it down, seeing it might help you visualize what the problem is asking... it always helped me... :-)
2006-10-10 22:34:47 · answer #2 · answered by Anonymous · 0⤊ 0⤋
I'm 11 and you the dumb dumb!! DUMB DUMB
2006-10-10 22:33:03 · answer #3 · answered by just ME 2 · 1⤊ 0⤋
Table ?????????/ What Table ?????????????
2006-10-10 22:38:12 · answer #4 · answered by ag_iitkgp 7 · 0⤊ 0⤋