A baseball is thrown at an angle of 26 degrees relative to the ground at a speed of 27.9 m/s. The ball is caught 62.5 m from the thrower.
The acceleration of gravity is 9.81 m/s^2
I found the time to be 2.492387686 s
How do I go about finding the height of the tallest point in the ball's path?
2006-10-10 15:15:31 · 5 answers · asked by wish1oh1 1 in Science & Mathematics ➔ Physics
Horizontal velocity = u cos x=(27.9).5*cos 26
=25.07635389 m/sec..............
Horizontal distance=horizontal velocity* time
time=62.5/25.07635389=2.492387859 seconds
=2.5seconds
Time to go to maximum height=2.5/2=1.25 seconds
use the formula
v^2-u^2=-2gh
0^2-(27.9 sin26)^2=-2(9.8)h
0-149.5864755=-19.6 h
h=7.632 meters
2006-10-10 15:31:02 · answer #1 · answered by Amar Soni 7 · 0⤊ 0⤋
Wow!! That's a tough one!! I bet if you increased the baseball velocity to 369.6 m/s and decreased the angle to 5% relative to the ground while aiming towards a cow standing next to a hippy, the baseball might go right through the cow knocking the hippy on his/her @ss...
What is the velocity of the baseball upon exiting the cow?
I have calculated this to be 27.9 m/s...the same answer of your problem. Now work some differential equations to find the speed at which it takes Mrs. Knowleton to make a peanut butter sandwich and you should, if I'm correct, have the answer to the meaning of The Gospel Of Mary...weird, huh?
2006-10-10 22:17:35 · answer #2 · answered by Billy 3 · 0⤊ 0⤋
You should have already learned that the horizontal motion is independent of the vertical motion. Therefore, the vertical velocity can be used to calculate the vertical kinetic energy, which can be equated to the potential energy at the top of travel.
Another approach is to recognize that the top of travel occurs at the exact midpoint in time of the travel. You can then use 1/2gt^2 to determine the height from which the ball fell.
2006-10-10 22:32:43 · answer #3 · answered by arbiter007 6 · 0⤊ 0⤋
Assuming it lands at the same height, note that the high point would occur exactly 1/2 of time or displacement. Go from there... If all else fails, plug everything into your handy projectile motion equation and the max x will occur at -b/2a
2006-10-10 22:21:21 · answer #4 · answered by John H 4 · 0⤊ 0⤋
Assume that the ball reaches the apex half-way into its flight.
Use trig to find the vertical component of the velocity (27.9 sin 26).
Find the height using h = v0 *t + .5at^2
h = (27.9 sin 26 * 1.245) + .5 (-9.81) (1.245)^2
h = 15.23 + (-7.6)
h = 7.63 meters
2006-10-10 22:24:55 · answer #5 · answered by Anonymous · 0⤊ 0⤋