solve for x and y: 96/x + 160/y=9 and 144/x + 160/y=11?

Answer 1

equation (2) - equation (1) => 48 /x = 2
=> x =24.

Replace x =24 into any of two equation
=> 160 /y = 5
=> y = 32

Answer 2

well, they both have 160/y so you can solve for one of them to that and use substitution. I used the first equation:
96/x + 160/y = 9 => 160/y = 9 - 96/x. Therefore,

144/x + (9-96/x) = 11 => (144-96)x + 9 = 11 => 48/x + 9 = 11 => 48/x = 2 => 48 = 2x => x = 24.

Than, I substituted that value of 24 into the first equation:

(96/24) + 160/y = 9 => 4 + 160/y = 9 => 160/y = 5 => 160 = 5y => y = 32

Thus, x = 24 and y = 32.