Help me???

Question

what is the solution to this set of inqualities

y > or equal to 2x+1
y < or equal to 2x-2
y > or equal to -3x+9

Answer 1

I think the only way to do this is to graph the inequalities. Then find the area on the graph where all 3 inequalities fit. To do this, draw each graph and shade the area that's fits for that graph. So, you would shade above the line y=2x+1 and below the line 2x-2 and above the line -3x+9. If there is a solution, then there will be an area on the graph where you shaded all three times

Answer 2

you need to graph each line with a solid line and shade in the region of solution...for y >=2x + 1 graph y intercept at 1 and go up 2 and right 1 for another point...the values above the line are the solution for that line...shae in a distince pattern

for y <= 2x - 2 y intercept is -2 and go up 2 and right 1 for another point...shade below that line because it is less than...again make the shading different from the other shading

for y >= -3x + 9 the y intercept is 9 and go down three and right one to get other points...because it is > shade above the line...

The solution is the area where all the shadings overlap

Answer 3

y = 0

Answer 4

0 > 2x+1
-1>2x
-1/2 > x

0 < 2x-2
2 < 2x
1 < x

0 > -3x + 9
3x > 9
x > 3

You have x > 3 and x < -1/2. These are mutually exclusive.

therefore, no real numbers satisfy all inequalities.

Solution is the empty set.