A car weighs 1.15 x 10^4 N. A force of 895 N is used to accelerate the car from rest to 25 m/s. How much time is required for the acceleration? ( ans. 33 secs )
can anyone help how the answer is solved?
2006-10-10 13:42:40 · 3 answers · asked by Bao Wow 3 in Science & Mathematics ➔ Physics
1. Find the mass of the car
2. Use f = ma to determine the acceleration on the vehicle
3. Use v = at to find the time required
1. m = F/a
= 1.15E^4 / 9.8 m/sec^2
= 1173.5 kg
2. 895 = 1173.5 * a
a = .763 m/sec^2
3. 25 = .763 t
t = 32.8 sec.
2006-10-10 13:54:09 · answer #1 · answered by Anonymous · 0⤊ 0⤋
(final velocity)= (initial velocity) + acceleration*time
just plug in the values and solve for time
oh yeah, F=ma. find the mass of the car by doing weight/9.8
This mass will be in kg. then find the acceleration with the same equation except now the force is 895 and the mass is what you just calculated. now you can put the values into the equation above
2006-10-10 20:48:37 · answer #2 · answered by Greg G 5 · 0⤊ 0⤋
Car Weight (vertical force due to gravity), F = mg
11500 = m x 9.81
hence m = 11500/9.81 = 1172kg.
A horizontal force of 895 Newton hence,
F = ma
895 = 1172 a
hence, a = 0.7635 ms-2
we know that a = (Vi -Vf )/ t ;
and let initial velocity Vi=0 ; and ; final velocity Vf = 25
Plug it in and you will get
0.7635 = (0 - (-25)) / t
Solve for t, and you will get 32.74s which rounding it off will be 33s
2006-10-10 20:56:41 · answer #3 · answered by Mr. Logic 3 · 0⤊ 0⤋