English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

1. r(t) =
2. r(t) =
3. r(t) =
4. r(t) =
5. r(t) =

2006-10-10 13:31:11 · 2 answers · asked by Faraz S 3 in Science & Mathematics Mathematics

2 answers

1,2 are smooth, 3,4,5 are not. For smoothness, the tangent vector cannot be the zero vector.

2006-10-10 13:42:46 · answer #1 · answered by James L 5 · 1 0

1 - smooth
Because if you take the derivative of this position function, you get r'(t) = <3t^2, 1, 9t^8>

It is never 0 for any t, therefore we can never get a location where the particle stops in space, which could give rise to a sharp corner in the graph. Since the particle is always moving, the path must be smoothly curved.

In all the other cases, look for where the derivative is completely the 0 vector. At that spot, you may have a place where the curve is not smooth.

2006-10-10 20:45:47 · answer #2 · answered by Alleghator 2 · 0 0

fedest.com, questions and answers