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f(x) = Xsquare + x

g(x)= Xcube + 1

2006-10-10 12:49:24 · 3 answers · asked by DK 2 in Education & Reference Homework Help

3 answers

You graph the fuctions by picking a few values of x, both positive and negative. The inverse function will have the axes reversed: the y-axis becomes the x-axis of the inverse function. Then there should be only one value for y for each x. Therefore, if the function has values on both sides of the y-axis for any portion of its range, the inverse is not a function.

2006-10-10 13:07:16 · answer #1 · answered by gp4rts 7 · 0 0

An inverse relation takes a relation y=f(x), and swaps x and y. If the unique relation is y=3x+a million, then the inverse relation is x=3y+a million. you are able to rewrite this (and graph it) as y=(x-a million)/3. using fact the inverse is defined everywhere, would be written explicitly in terms of x, and with out the +/- that comes once you're taking the sq. root of the two factors, it must be a function. often, the inverse -- of a real-valued, continuous function of the genuine numbers -- is a function on each and every occasion the unique function is precisely monotonic, it particularly is, continuously-increasing or continuously-lowering. this is the case with non-consistent linear purposes which comprise f(x)=3x+a million

2016-10-19 04:17:11 · answer #2 · answered by ? 4 · 0 0

you use the pencil/vertical line test. Or you look to see if they are reflections across the y=x line.

2006-10-10 13:01:24 · answer #3 · answered by Anonymous · 0 0

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