a sphere that wieghs 100 N rests in the angle formed by two boards 90 degrees apart. the boards are very smooth so the only forces they exert on the sphere are perpendicular to thier surface. find the magnitude of each of these forces.
2006-10-10 12:45:49 · 3 answers · asked by micheal j 1 in Science & Mathematics ➔ Physics
it is arranged like \0/ except that the \ / represent the 2 boards which are 90 degrees apart and the 0 represents the sphere
2006-10-10 13:32:26 · update #1
the boards are subsequently 45 deg above horizontal.
2006-10-10 13:34:00 · update #2
Without any info on how the boards are arranged relative to the force of gravity, the ? has no answer. If they are each at 45 deg above horizontal then the vertical component of each force must equal 50 N. Ergo, the normal force must equal 50*sec45deg = 50*root2 = 70.7 N
2006-10-10 13:24:30 · answer #1 · answered by Steve 7 · 1⤊ 0⤋
I may be wrong, it's been a while, but I believe each board exerts 50N of force back to the ball. If due to gravity the ball gives 100N and the ball is no longer moving, that would mean that something is equaling that potential force in the opposote direction. Since both boards are equal in dimensions and general desigh, the most either could give without making the ball actually rise up is 50N. That's the way I see it anyhow.
2006-10-10 19:57:54 · answer #2 · answered by xxplalmxx 3 · 0⤊ 0⤋
Steve is right. Another way to explain: the resultant of the 2 normal forces must be a vertical force equal to 100N. The vector math you have been learning should give you the same value Steve said.
2006-10-10 22:06:35 · answer #3 · answered by sojsail 7 · 0⤊ 0⤋