This is a brain teaser for school I tried but I can't figure out the answer why don't you try?:
In the year 1201, a woman was 35 years old. In the year 1206, the same woman was 30. How is this possible?
2006-10-10 12:27:29 · 9 answers · asked by jmgirl820 1 in Education & Reference ➔ Homework Help
That's simple hun, the years are B.C. which would mean as we get closer and closer to the year christ was born, you are getting older and older. understand?
2006-10-10 12:31:18 · answer #1 · answered by Anonymous · 0⤊ 0⤋
1201 and 1206 BC
2006-10-10 12:29:41 · answer #2 · answered by Anonymous · 0⤊ 0⤋
The time is B.C.
1206 B.C. she was 30
1205 B.c. she was 31
1204 B.C. she was 32
1203 B.C. she was 33
1202 B.C. she was 34
and...
1201 B.c. she was 35
2006-10-10 12:57:31 · answer #3 · answered by Melissa F 5 · 0⤊ 0⤋
The dates are B.C. rather than A.D.
My daughter had the same question last week.
2006-10-10 12:30:52 · answer #4 · answered by ????? 7 · 0⤊ 0⤋
The dates are B.C rather than A.D
2006-10-10 12:35:14 · answer #5 · answered by Riviera_ 4 · 0⤊ 0⤋
The dates are B.C. rather than A.D.
2006-10-10 12:36:20 · answer #6 · answered by nighthawk_842003 6 · 0⤊ 0⤋
i'm going to set it up for you: x = fee in line with orange; y = fee in line with apple. 17x + 7y = 5.36 8x + 5y = 3.sixty 8 sparkling up the 1st equation for x. Then plug the fee for x into the 2d equation and sparkling up that one for y. ultimately, take the fee for y and plug it decrease back into the 1st equation to locate the fee for x.
2016-12-13 05:58:38 · answer #7 · answered by Anonymous · 0⤊ 0⤋
Because the year was B.C.E. This is not a hard one.
2006-10-10 12:29:33 · answer #8 · answered by Oh Dee! 3 · 1⤊ 0⤋
challenging factor. seek from google. that might help!
2014-11-04 19:23:14 · answer #9 · answered by Anonymous · 0⤊ 0⤋