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A)what does the ionization energy quantitatively measure about an atom?
B)why do ionization energies decrease from the top to the bottom of the group on the periodic table of elements?
C)why do ionization energies increase from left to right across any period?

i have absolutely no idea, i cant find it in my note

2006-10-10 12:26:21 · 3 answers · asked by um yea hi 4 in Science & Mathematics Chemistry

3 answers

A)
It is the energy required to strip it of an electron. More generally, the nth ionization energy is the energy required to strip it of an nth electron after the first n − 1 have already been removed. It is centrally significant in physical chemistry as a measure of the "reluctance" of an atom or of a molecule to surrender an electron, or the "strength" by which the electron is bound.

B)
Ionization energy exhibits a strong negative correlation with atomic radius.

C)
To achieve a stable octet, elements on the left looks to lose an electron(s), while elements on the right looks to gain an electron(s).

2006-10-10 12:30:00 · answer #1 · answered by lufen 3 · 0 0

A) Amount of energy required to take out an electron from an atom (kj or joules)
B) Ionization energies decrease from top to bottom because number of shells increase i.e energy levels increase.
C) Ionization energies increase from left to right across a period because number of valence electrons increase on a same energy level i.e. increase in proton pull.

2006-10-10 13:14:03 · answer #2 · answered by Fatima A 3 · 0 0

you're partly stunning - the explanation has to do with the version in length of the climate which of direction is contemplated of their order on the periodic table. i've got self assurance the forces that carry the electrons are proportionate to a million/r^2. So for each doubling of the radius you get a 4 fold shrink interior the ionization power. So the substantial element is the dimensions of the element.

2016-12-13 05:58:32 · answer #3 · answered by Anonymous · 0 0

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