it is (2x)^2+2(2x)(3)+(3)^2
=4x^2+12x+9
2006-10-10 12:17:20
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answer #1
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answered by raj 7
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The easiest way to look at this is to think about a regular number squared. Let's say 4^2. All this means is '4 times 4' easy, right? Your problem is (2x+3)^2. So just write it out like I wrote out the 4 ^2 above. It will look like, (2x+3)(2x+3), now use the FOIL method and get what the others have stated 4x^2 +12x + 9
By the way, if you want to know what x equals, just set what's inside the parenthesis equal to zero and solve for x.
2x+3 = 0
then subtract 3 from each side, 2x + 3 - 3 = 0 - 3
2x = -3
then divide each side by two to
get the x by itself 2x/2 = -3/2
x = -3/2
2006-10-10 19:54:52
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answer #2
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answered by kevvsworld 3
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I got
4x^2 +2(2x)(3) + 3^2 = 4x^2 + 12x + 9
:-)
2006-10-10 19:26:32
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answer #3
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answered by Anonymous
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(2x + 3)^2 = (2x + 3)(2x + 3) = 4x^2 + 6x + 6x + 9 = 4x^2 + 12x + 9
you can't multiply the coefficients then square that value to get the middle.
2006-10-10 20:09:00
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answer #4
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answered by Sherman81 6
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the original problem is: (2x+3)^2
the way i learned is put a 2 outside of the quantity
like this: 2(2x+3)^2
take 2x times itself. then take 3 times 2x times the two outisde the quantity. and then take 3 times 3.
This is my answer: 4x^2+12x+9
2006-10-10 19:58:12
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answer #5
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answered by pooh 1
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4x^2+12x+9 is the correct answer.
razor
2006-10-10 19:17:47
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answer #6
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answered by Anonymous
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MY answer is 4x^2+12x+9
2006-10-10 19:15:38
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answer #7
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answered by Sean 1
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its in this form (a+b)^2
which is solved in following manner
a^2 + 2ab + b^2
therefore, (2x+3)^2 = 4x^2 + 12x + 9
2006-10-10 20:05:15
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answer #8
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answered by Fatima A 3
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(2x + 3)(2x +3)
4x² + 6x + 6x + 9
4x² + 12x + 9
a = 4
b = 12
c = 9
to find x use the quadratic equation:
x=(-b+/-sqrt(b^2-4ac))/(2a).
(5)
This equation is known as the quadratic formula.
PS: x will have TWO values.
2006-10-10 19:19:49
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answer #9
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answered by Anonymous
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2^2(x^2)+3^2 using Distributive Property
4x^2+9
that's as much as you can simplify it
2006-10-10 19:18:29
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answer #10
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answered by Laura 2
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