any math wiz's out there?

Question

I need help with my review, i've tried all ican to figure out this problem but i just can't figure out how to do it. Can anyone show me step by step how they did it so i know how to on my pre-calc test tomorrw?

2x^4-13x³ +12x² +52x-80 when (2x-5) is one of the factors.

Answer 1

Ah, polynomial long division. You do this just as you would do long division with numbers. Write 2x - 5 goes into 2x^4 - 13x^3 + 12x^2 + 52x - 80. Start with 2x goes into 2x^4, which is x^3. Multiply 2x - 5 by x^3 and subtract from the longer polynomial, leaving -8x^3 + 12x^2 + 52x - 80. 2x goes into the first term -4x^2 times. Multiply 2x - 5 by that and subtract again, leaving -8x^2 + 52x - 80. 2x goes into the first term -4x times, multiply and subtract to leave 32x - 80. 2x - 5 goes into that entire expression an even 16 times. If you've been writing the quotients up above all along, as you would with regular long division, you'll have x^3 - 4x^2 - 4x + 16. You can then factor that as x^2(x - 4) - 4(x - 4) = (x^2 - 4)(x - 4) = (x + 2)(x - 2)(x - 4). So 2x^4 - 13x^3 + 12x^2 + 52x - 80 = (2x - 5)(x + 2)(x - 2)(x - 4).

Answer 2

2x^4-13x^3 +12x^2 +52x-80

Maybe you want to factor this expression.

If you do the long division, (2x - 5) into the original expression, you get

x^3 - 4x^2 - 4x + 16

You can factor x^2 from the first two terms, and 4 from the last two terms.

x^2(x - 4) - 4(x - 4)

Which can be written as

(x^2 - 4)(x - 4)

And x^2 - 4 is a difference of two squares, and factors as

(x + 2)(x - 2)

So the factors of 2x^4-13x^3 +12x^2 +52x-80 are

(2x - 5)(x + 2)(x - 2)(x - 4)

Answer 3

locate out how many quarters in a pound, or in 5 pounds and do the maths. for example permit's say that there is $2 properly worth of quarters in a pound (in basic terms guessing) multiply that by 35 and you get $70