how do you solve a problem such as x2 -44 = 496 + 7x?

Question

the x2 is suppose to be the x's exponent

Answer 1

Rearrange:
x^2 - 7x - 540 = 0

Factor:
(x+20)(x-27) = 0

so x=-20 or x=27.

(or you can use the quadratic formula and compute x = (-b +/- sqrt(b^2-4ac))/(2a) )

Answer 2

Hi,
First must put all figures on left hand side and all equal to 0.

x^2 -44 = 496 + 7x
or x^2 -7x -540 = 0
Now to factorise this.
Look at -540 and see what factors it has.
Example: 9 and -60 are factors
But when the factors are added together they must make -7 i.e the value of x.

Choose a value that the difference is -7.
Say 20 and then the other factor is -27.
These when added together yield -7 which is what you want.

So now have ( x +20)(x-27) =0
Therefore x+ 20 =0 and x- 27=0
Or x=-20 and x = 27 are the solutions.

This is just the short way. The other way is to use the formula as mentioned above from your earlier answerer.

:-)

Answer 3

x^2 - 44 = 496 + 7x

Subtract 7x from both sides, subtract 496 from both sides

x^2 - 7x - 540 = 0

Giving you a quadratic equation which, hopefully can be factored.

The prime factors of 540 are 2, 2, 3, 3, 3, 5 and we need to find two factors of 540 with a difference of 7.

2*2*5 = 20
3*3*3 = 27

So the factors of the equation are

(x - 27)(x + 20)

The product of these factors is zero when either of the factors = zero.

x - 27 = 0
x = 27

x + 20 = 0
x = - 20

Its always a good idea, time permitting, to check the determined vallues of x in the original equation.

Answer 4

x² + 7x ? a million = 0 think of of this as though it have been ax² + bx + c = 0. Subtract the c-area, ?a million. x² + 7x = a million // Multiply by fours circumstances the a-area, a million. 4x² + 28x = 4 // upload the b-area, 7, squared. 4x² + 28x + 40 9 = fifty 3 // Now the left part is a appropriate sq., component it out. (2x + 7)² = fifty 3 // Take the sq. root of the two part. fifty 3 is a chief. (2x + 7 = ±?fifty 3)?(?(2x + 7) = ±?fifty 3) you may now resolve those 2 like a typical equation. (2x + 7 = ±?fifty 3)?(?(2x + 7) = ±?fifty 3) // Subtract 7 from the 1st equation, component out the damaging from the 2nd and subtract 7 too, combining the two. 2x = {?7 ± ?fifty 3, ?7 ? ?fifty 3} // Divide by 2. x = {?3.5 ± 0.5?fifty 3, ?3.5 ? 0.5?fifty 3} // Simplify. answer: x = ?3.5 ± 0.5?fifty 3 the respond does not simplify any further. ?fifty 3 is an irrational selection and to place in writing down an equivalent decimal-in basic terms type could take perpetually, actually. Approximations injury percision anyhow. That replaced into the quadratic formulation utilized. The quadratic formulation is: ax² + bx + c = 0, a ? 0 ? x = (?b ± ?(b² ? 4ac))/(2a) it quite is a competent concept to bear in mind the formulation, because of the fact the tactic is extra solid to bear in mind. I in basic terms bear in mind the tactic because of the fact of tricks from the formulation. factors: the standards of x² + 7x ? a million are a pair of x minus the 0, the pairs are the plus version of the 0 and the minus version. (x + 3.5 + 0.5?fifty 3)(x + 3.5 ? 0.5?fifty 3) = x² + 7x ? a million // think of of this as (a + b)(a ? b) = a² ? b², the place a = x + 3.5 and b = 0.5?fifty 3 (x² + 7x + 12.25) ? 13.25 = x² + 7x ? a million // upload like words. x² + 7x ? a million = x² + 7x ? a million // evaluate real. examine: x² + 7x ? a million = 0, x = ?3.5 ± 0.5?fifty 3 // Plug in x. (12.25 ? 3.5?fifty 3 + 13.25) + (?24.5 ± 3.5?fifty 3) ? a million = 0 // Cancel out the damaging and beneficial ±3.5?fifty 3's. 12.25 + 13.25 ? 24.5 ? a million = 0 // upload. 0 = 0 real. Q.E.D.

Answer 5

you have to reduce it to the form, ax^2 + bx + c = 0

in your case this is:

x^2 - 7x - 540 = 0

so you have, a = 1, b = -7, c = -540

which you can solve using the formula

x = (-b +/- sqrt(b^2 - 4*a*c)/2*a

x = (7 +/- 47)/2

so you have:

x1 = (7+47)/2 = 27 this is your 1st solution

x2 = (7-47)/2 = -20 this is your 2nd solution

Answer 6

X2 - 7x = 540

x = 27

Answer 7

x^2-7x-540=0
(x-27)(x+20)=0
x=27, x=-20

Answer 8

x^2-7x-540=0
540=1*540
2*270
3*180
4*135
5*108
6*90
9*60
10*54
12*45
20*27
x^2-27x+20x-500=0
(x+20)(x-27)=0
x=-20 or 27

Answer 9

Do whatever math is necessary to get all the x's on one side of the = sign, and all the numbers on the other side.

Answer 10

Go to some maths toutor in ur city