solving equations using two or more transformations.
2006-10-10 11:31:13 · 11 answers · asked by john h 1 in Science & Mathematics ➔ Mathematics
add 7 to both sides
3x = 30
then divide by 3
x=10
2006-10-10 11:32:40 · answer #1 · answered by Melody 3 · 0⤊ 0⤋
3x-7=23
3x=23+7
3x=30
x=30/3
x=10
2006-10-11 09:14:51 · answer #2 · answered by srirad 2 · 0⤊ 0⤋
The answer to this question is: x= 10, because if 3 x 10= 30 - 7 = 23.
2006-10-10 18:32:48 · answer #3 · answered by neopetsrockstar10 2 · 0⤊ 0⤋
so the answer to this is x=10 because 3 multiply by 10 is 30 subtracted by 7 is 23 so u can write 3(10)-7=23 then 30-7=23
2006-10-10 18:38:10 · answer #4 · answered by Anonymous · 0⤊ 0⤋
3x - 7 = 23 add 7 to each side
3x=23+7=30 divide by 3
3x/3=30/3
x=10
2006-10-10 18:42:46 · answer #5 · answered by yupchagee 7 · 0⤊ 0⤋
x=10
2006-10-10 18:40:14 · answer #6 · answered by ? 4 · 0⤊ 0⤋
3x/3 - 7/3=23/3
x - 2 1/3 = 7 2/3
x - 2 1/3 + 2 1/3 = 7 2/3 + 2 1/3
x=9 3/3
x=10
3x - 7 = 23
3x - 7 - 23 =23-23
3x -30 =0
(3x-30)/3=0
x-10=0
x=10
2006-10-10 18:53:11 · answer #7 · answered by albert 5 · 0⤊ 0⤋
3x - 7 = 23
3x = 16
x = 5 1/3
2006-10-10 18:34:05 · answer #8 · answered by rocketman9070 5 · 0⤊ 0⤋
3x-7=23
3x=30
x=10
2006-10-10 18:43:05 · answer #9 · answered by shmux 6 · 0⤊ 0⤋
3x - 7 = 23
3x = 30
x = 10
Didn't I just answer this?
2006-10-10 18:33:20 · answer #10 · answered by JennyAnn 4 · 0⤊ 0⤋