Acceleration = Change in velocity / Time
2006-10-10 11:35:27
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answer #1
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answered by the.chosen.one 3
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There are several. The defining equation is a = dv/dt, where both a and v are vectors. Other equations exist to permit determining acceleration from various combinations of time, distance, intial and final velocity, et cetera.
2006-10-10 11:28:00
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answer #2
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answered by Anonymous
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Acceleration = distance/(time)^2
2006-10-10 11:31:26
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answer #3
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answered by Scott S 4
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you will get the acceleration from a = (v - u)/t = (60 - 0)/t = 60/t learn it from v^2 - u^2 = 2as a = (v^2 - u^2)/2s = 60^2/(2s) you will would desire to alter the units. define the braking ability because of fact the deceleration to take a seat down returned. At 60 hit the brake and degree the time and distance to return to take a seat down returned. Use the above 2 equations returned. ability and torque are much less easy. they provide the effect of being a function of RPM and acceptable at distinctive values of RPM.
2016-12-26 15:32:36
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answer #4
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answered by ? 3
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It depends on what you are given. I will mention a method that I no one else has just in case it fits your problem.
If you are given the force pushing on an object and the mass of the object, you would find the accereration using the equation,
F = ma, or a = F/m
2006-10-10 11:35:03
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answer #5
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answered by Anonymous
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f (t) = position with respect to time
f ' (t) = velocity with respect to time
f " (t) = acceleration with respect to time
Johnny O's distance over time is velocity NOT acceleration
2006-10-10 11:33:13
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answer #6
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answered by BoredomStrikes 3
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Rate = Distance/Time
2006-10-10 11:26:27
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answer #7
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answered by Johnny O 2
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acceleration = change in velocity / change in time
or
a = (v2 - v1)/(t2 - t1)
2006-10-10 11:28:50
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answer #8
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answered by tlf 3
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