we got this in physics and i don't know how to do it. could you try to explain it to me? Thanks.
A box is sliding down a 38.8 degree incline at constant velocity. What is the coefficient of friction??
2006-10-10 11:08:40 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Physics
coefficient of friction = tan(38.8)=.8
2006-10-10 11:13:40 · answer #1 · answered by bruinfan 7 · 0⤊ 0⤋
You need to know the mass of the box to answer this question. If you find the mass, take this times 9.81 and multiply this by the sin of 38.8. This will give you the force of gravity that is parralel to the motion of the box. Then you need to take the mass times 9.81 and multiply this by the cos of 38.8. This will give you the normal force. Take the force of gravity parralel and devide by the normal force and this is the coefficient of friction. Without the mass this cannot be done.
2006-10-10 18:15:02 · answer #2 · answered by slingerkyle 1 · 0⤊ 0⤋
Resolve the weight of the box into vector components, one pointing perpendicular to the incline, and one parallel to it. (Trivial exercise in trigonometry.) The ratio of the magnitudes must be the coefficient of friction.
2006-10-10 18:31:33 · answer #3 · answered by Anonymous · 0⤊ 0⤋
There's got to be an equation in your book. One with G (gravity) and A (angle) in it or something like that.
2006-10-10 18:10:52 · answer #4 · answered by Chuglon 3 · 0⤊ 0⤋
Do you want someone to *explain* it to you or *do* it for you?
I'm afraid I can't do either.
2006-10-10 18:10:42 · answer #5 · answered by Anonymous · 0⤊ 0⤋
try using Phys.org or something like it
2006-10-10 18:17:52 · answer #6 · answered by Sky 2 · 0⤊ 0⤋