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"The news has reached me that one day a customer brought into the shop of Abdul the Jeweler six chains, each of which had five links. He wanted the six chains to be joined into one large circular chain and inquired as to the cost. "Well,' replied the jeweler, 'every link I cut open and close costs one piece of silver.' The question, Your Majesty, is how many pieces of silver are required for the job?"


SHOW WORK PLEASE

2006-10-10 10:10:47 · 5 answers · asked by yankee_914 1 in Science & Mathematics Mathematics

5 answers

Let's see... six chains (5 links each) formed into a loop. The job doth requireth *five* silver pieces.

Someone might intuitively think to open a link at the end of each piece and connect it to the next and finally open a link and connect it to the first. That would be *six* silver pieces.

However, being the magnificiently intelligent ruler I am, I figure that I can open all *five* links in one of the chains and use those links to connect the *five* remaining chains. That would cost only *five* silver pieces.

If anyone is willing to pay me six pieces of silver for this job, I will gladly pocket the extra silver piece and pay the jeweler to do it for *five* silver pieces.

2006-10-10 10:14:17 · answer #1 · answered by Puzzling 7 · 0 0

6

2006-10-10 17:18:18 · answer #2 · answered by kacak15348 1 · 0 0

6 peices
you have 6 chains
cut a link open from the first chain and close it on the second..1
open a link on the second chain and close it on the third...2
open a link on the third chain and close it on the fourth...3
open a link on the fourth chain and close it on the fifth...4
open a link on the fifth chain and close it on the sixth...5
take the other end of the sixth chain and bring it around open a link and close it on the other side of the first chain...6

2006-10-10 18:26:53 · answer #3 · answered by Anonymous · 0 0

5 1 chain you unlink all the rings and use to join the other five chains together

2006-10-10 17:16:10 · answer #4 · answered by warwor 1 · 0 0

The answer is 6 silver pieces
Its common in a circle.
No working, think well.
You will understand.

2006-10-10 17:17:00 · answer #5 · answered by syam p 2 · 0 0

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