If density of a gas is 1.2 g/L at 0.98026 atm and 293 L, what is the molecular mass ?
I solved this using MW = (mRT)/PV and got 29.44 g. is this correct? MW is molecular weight and m comes from n (moles)= m (mass)/MW (molecular weight.)
plz help! THANKS!
2006-10-10 09:54:41 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
I MEAN 293 K, NOT L!!! SORRY BOUT THAT!
2006-10-10 09:55:05 · update #1
pV = nRT but n = m/MW so pV = mRT/MW. Solving for MW we get:
MW = mRT/pV, but m/V = d (density) so:
MW = dRT/p
MW = 1.2*0.082*293/0.98026
MW = 29.41 a.m.u.
so you are correct!!
2006-10-10 10:32:30 · answer #1 · answered by Dimos F 4 · 0⤊ 0⤋
there's a lacking component to the subject: we could understand the suited temperature. It makes a huge difference. If the suited temperature is 4 hundred ok, then basic arithmetic will do the trick; if something, you will could regulate the quantity proportionately to the suited temperature. the uncomplicated deal here is PV = nRT, and you may compute the stress, you already know n, you may look up R, you already know T, and from this you may compute the quantity. And which will inform you the place the piston is.
2016-10-16 01:20:13 · answer #2 · answered by ? 4 · 0⤊ 0⤋
Yes you are correct.
2006-10-10 10:10:46 · answer #3 · answered by syam p 2 · 0⤊ 0⤋
i think yes
2006-10-10 10:15:50 · answer #4 · answered by source_of_love_69 3 · 0⤊ 0⤋