Factoring Trinomials
2006-10-10 09:49:09 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
no
18x^5 + 15x^4z - 75x^3z^2
= 3x^3(6x^2 + 5xz - 25z^2)
= 3x^3(3x - 5z)(2x + 5z)
2006-10-10 09:58:16 · answer #1 · answered by Scott R 6 · 0⤊ 0⤋
Each term includes at least a factor of 3, and a x^3, so factor those out:
3x^3(6x^2 + 5xz - 25z^2).
To factor 6x^2 + 5xz - 25z^2: you can try factorizations of the form
(ax+bz)(cx+dz)
where ac=6, bc+ad=5, and bd=-25. b and d should be of opposite signs, so that their product is negative.
If you try combinations such as a=2 and c=3, or a=6 and c=1, to get ac=6, then you will get it, but your current answer is not quite correct.
2006-10-10 09:58:36 · answer #2 · answered by James L 5 · 0⤊ 0⤋
error in factoring the trinomial
(6x+5z)(x-5z)
6x^2-30xz+5xz-25z^2
6x^2-25xz-25z^2 off by 30xz
18x^5+15x^4z-75x^3z^2 1st factor 3x^3
3x^3(6x^2+5xz-25z^2) now factor the trinomial
3x^3*(3x-5z)(2x+5z)
check
(3x-5z)(2x+5z)
6x^2+15xz-10xz-25z^2
6x^2+5xz-25z^2
3x^3(6x^2+5xz-25z^2)
18x^5+15x^4z-75x^3z^2
2006-10-13 09:00:37 · answer #3 · answered by yupchagee 7 · 0⤊ 0⤋
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2016-12-08 12:23:03 · answer #4 · answered by motato 4 · 0⤊ 0⤋
Nope:
3x^3(6x^2+5xz-25z^2)
3x^3(2x+5z)(3x-5z)
Your answer would get
3x^2(6x^2-25xz-25z^2)
2006-10-10 10:00:16 · answer #5 · answered by T 5 · 0⤊ 0⤋
can u rite the equation any better than that becuz it looks like 15x is being raised to 4z-75.....
2006-10-10 09:56:59 · answer #6 · answered by people suck 6 · 1⤊ 1⤋