First, attempt to put each combination into prime factors. For example, 14 and 21:
14= 7 x 2
21 = 7 x 3
The LCM would be 7, the only number they have in common. The GCF would be 7 x 2 x 3 or 42.
Another example
10 = 5 x 2
12 = 6 x 2 = 3 x 2 x 2
The LCM is 2, the GCF is 5 x 2 x 6 or 60.
Another:
15 = 5 x 3
25 = 5 x 5
LCM is 5, GCF is 5 x 5 x 3 or 75
One more:
6 = 3 x 2
15 = 3 x 5
LCM is 3, GCF is 3 x 2 x 5 or 30
2006-10-10 10:48:35
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answer #1
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answered by Anonymous
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14, 21 = 7
10, 12 = 2
15, 25 = 5
6, 15 = 3
36, 27 = 9
22, 33 = 11
60, 20 = 20
12 , 9 = 3
24, 16 = 8
45, 20 = 5
12, 42 = 6
30, 50 = 10
36, 12 = 12
100, 250 = 50
24,30 = 6
8, 15 = 1
12, 28 = 4
18, 40 = 2
64, 16 = 16
30, 75 = 15
54, 180 = 18
2006-10-10 09:45:42
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answer #2
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answered by amir11elad 2
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You are wanting to find what common number can both of 39 and 26 be divided. In this case, it will be 13. Usually you can use 2, 2 and so on and then just multiply them altogether. However, you can't do that for this question. So just keep trying and you'll find that the only common number both 39 and 26 can be divided by is 13. This will give you a remainder of 3 and 2 respectively and there are no more common number for 3 and 2.
2016-03-28 04:01:35
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answer #3
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answered by Anonymous
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Use Euclid's algorithm. I'll illustrate.
GCF(180,54):
180/54 = 3, with a remainder of 18
54/18 = 3, with a remainder of 0.
Stop. The GCF is 18.
To compute GCF(a,b), let a be the larger number. Divide a by b, and compute the remainder r. Then compute GCF(a,b) with a=the old b, and b=r. Once the remainder is 0, then b is the GCF.
2006-10-10 09:39:47
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answer #4
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answered by James L 5
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to find it write all the factors of each number in a list.
The greatest number that occurs on both is the GCF
2006-10-10 09:36:16
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answer #5
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answered by spens 2
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geez!!
that's a lot of #'s to find the gcf's for.
for each #, just write down all of their factors, and find the ones that are the same.
2006-10-10 10:12:10
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answer #6
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answered by luvsoccer53 2
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pay me and I'll tell you.... you HAVE to be kidding!
2006-10-10 09:37:34
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answer #7
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answered by Anonymous
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