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I need help understanding electron configurations and electron configuration tables. The electron configuration for tin(Sn) is:
Sn: 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p2

(The number after the letter is the number of electrons if you didn't know)
I am confused because the E.C. table has sublevel f. why did the configuration go from 4d10 to 5s2? It skipped the f sublevel. Why is that?
THanx 4 ur help!

2006-10-10 09:31:06 · 5 answers · asked by i ♥ music! 2 in Science & Mathematics Chemistry

5 answers

Because they overlap...you'd have to go with the diagonal rule. Do you know what that is? Sh!t, it's hard to explain here...Umm...

Overlapping orbitals...because as we get farther away from the nucleus, electrons are closer and contain more sublevels.

1s
2s
2p 3s
3p 4s
3d 4p 5s
4d 5p 6s
4f 5d 6p 7s
5f 6d 7p 8s

(Draw arrows) Go from 1s to 2s, then 2p to 3s, then 3p to 4s, then 3d to 4p to 5s, then 4d to 5p to 6s, then 4f to 5d to 6p to 7s, then to 5f to 6d to 7p to 8s

Did this help?

(Note: The indentation is opposite than what I can make it. The 1s should start farthest to the right, and the 5f on the last line should be closest to the left.)

2006-10-10 09:42:16 · answer #1 · answered by Elizabeth R 3 · 0 0

you reversed something. look at a periodic table when you are figuring electron configurations and you'll see the pattern. here's the whole thing:

1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 6s2 4f14 5d10 6p6 7s2 5f14 6d10 7p6. that's for the whole periodic table. theoretically it can keep going as they create more elements. (the last elements are synthetic. and the last element created is Uuo. Ununoctium. the electron configuration i gave for you is for this element.) but, look at a periodic table and compare it to an electron configuration. you should see the pattern.

2006-10-10 09:43:28 · answer #2 · answered by practicalwizard 6 · 0 0

it incredibly is sulfur. certainly, you're removing your periodic table. 1s^a million is H, 1s^2 is He, 2s^2 is Be, etc. For the s orbitals, the extensive kind in front (1s, 2s, 3s) is the extensive kind row. So 4s might start up with ok, then Ca, etc. The exponent extensive kind is the kind of electrons interior the orbital with a optimal of two electrons in line with orbital, and because there is just one s orbital, it could purely carry 2. whilst the exponent is a million, it incredibly is the element interior the 1st column (alkali metals), and whilst it fairly is two, it incredibly is the 2d column (alkaline earth metals). There are 3 p orbitals that could carry 2 electrons each, so in finished they carry 6. p orbitals start up on the 2d row, so there is not any such element as a 1p orbital. As with the s orbital, the extensive kind in front of the p (2p, 3p, 4p) is the extensive kind row. The exponent is the extensive kind column, with exponents a million, 2, 3, 4, 5, 6 being the element in communities 13, 14, 15, sixteen, 17, 18 respectively. As on your question, you will see with all the s orbitals filled (exponents are 2) and the 2p^6 that those are finished. 3s^2 is likewise finished, so which you look at 3p^4. 3 skill it incredibly is interior the 0.33 row with Na and Mg. p orbitals are on the stunning area of the periodic table. 4 skill it incredibly is in group sixteen, the oxygen family individuals. watching the 0.33 row in group sixteen, the element is sulfur. you may look at a textbook for a extra useful description.

2016-12-13 05:52:11 · answer #3 · answered by ? 4 · 0 0

The electron confiqurations for transition metals skip around some.

2006-10-10 09:35:01 · answer #4 · answered by spens 2 · 0 0

4f is higher in energy than 5s, so 5s fills first. 4f only starts filling around lanthanum, hence the lanthanides.

2006-10-10 09:36:33 · answer #5 · answered by Gervald F 7 · 1 0

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