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2006-10-10 08:15:56 · 17 answers · asked by parisi92 1 in Science & Mathematics Mathematics

17 answers

-i/11 and i/11.

2006-10-10 08:19:04 · answer #1 · answered by gjmb1960 7 · 2 1

The square root of a negative number is complex (involving i).

121 is a perfect square, ie 11^2.

So the answer is i/11.

2006-10-10 15:18:32 · answer #2 · answered by Draco Moonbeam 3 · 0 0

In the set of complex numbers, there are 2 square roots of -1/121
i/11 and -i/11

If the problem has -1/121 under a square root sign, then the answer is i/11

In the set of real numbers, it would not exist.

2006-10-10 15:25:02 · answer #3 · answered by Melody 3 · 0 1

Square root of a negative number

√- 1/121 =

i/11

- - - - - - - - - - - - - - - - s-

2006-10-10 15:27:10 · answer #4 · answered by SAMUEL D 7 · 0 1

j/11 and -j/11 where j is the sqrt of (-1).

(engineers use j for the imaginary root !)

also written as +/-(1/11)e^(j*pi/2).

Now when you express the roots this way (as points on the unit circle on the real-imaginary plane) then one can see that there are infinite numbers of roots that will be the answer.

They are of the form
(1/11)e^(j*pi/2+n*pi) for n= 0,1...infinity

2006-10-10 15:38:19 · answer #5 · answered by Anonymous · 0 0

-1/11

2006-10-10 15:37:22 · answer #6 · answered by Milos 1 · 0 1

i/11

2006-10-10 16:04:40 · answer #7 · answered by Anonymous · 0 0

i/11

2006-10-10 15:58:31 · answer #8 · answered by Dr. J. 6 · 0 0

i/11

2006-10-10 15:23:43 · answer #9 · answered by statistics 4 · 0 0

i/11

2006-10-10 15:18:44 · answer #10 · answered by Jared Z 3 · 0 0

i/11

2006-10-10 15:18:30 · answer #11 · answered by jacinablackbox 4 · 0 0

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