-i/11 and i/11.
2006-10-10 08:19:04
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answer #1
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answered by gjmb1960 7
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The square root of a negative number is complex (involving i).
121 is a perfect square, ie 11^2.
So the answer is i/11.
2006-10-10 15:18:32
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answer #2
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answered by Draco Moonbeam 3
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In the set of complex numbers, there are 2 square roots of -1/121
i/11 and -i/11
If the problem has -1/121 under a square root sign, then the answer is i/11
In the set of real numbers, it would not exist.
2006-10-10 15:25:02
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answer #3
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answered by Melody 3
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Square root of a negative number
â- 1/121 =
i/11
- - - - - - - - - - - - - - - - s-
2006-10-10 15:27:10
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answer #4
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answered by SAMUEL D 7
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j/11 and -j/11 where j is the sqrt of (-1).
(engineers use j for the imaginary root !)
also written as +/-(1/11)e^(j*pi/2).
Now when you express the roots this way (as points on the unit circle on the real-imaginary plane) then one can see that there are infinite numbers of roots that will be the answer.
They are of the form
(1/11)e^(j*pi/2+n*pi) for n= 0,1...infinity
2006-10-10 15:38:19
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answer #5
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answered by Anonymous
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-1/11
2006-10-10 15:37:22
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answer #6
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answered by Milos 1
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i/11
2006-10-10 16:04:40
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answer #7
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answered by Anonymous
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i/11
2006-10-10 15:58:31
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answer #8
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answered by Dr. J. 6
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i/11
2006-10-10 15:23:43
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answer #9
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answered by statistics 4
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i/11
2006-10-10 15:18:44
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answer #10
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answered by Jared Z 3
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i/11
2006-10-10 15:18:30
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answer #11
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answered by jacinablackbox 4
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