Given the length of the 3 sides of a triangle. Find the one that is impossible?
a) (5,5,11) b)(6,4,9) c)(4,3,8) d)(5,5,5)
with steps plz..
2006-10-10 07:41:14 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Triangle Inequality Theorem
The sum of the lengths of any two sides is greater than the length of the third side.
The following cannot be true
(4,3,8)- The sum of side with length 4 plus the side of length 3 is not greater than 8
(5,5,11) - The sum of side with length 5 plus the side with length 5 is not greater than 11
2006-10-10 08:26:25 · answer #1 · answered by Koala Bear 3 · 0⤊ 0⤋
a) 5, 5, 11
1) draw a line 11 cm long.
2) using a compass, draw a 5cm circle around 1 end of the line
3) now draw a 5cm circle around the other end.
These circles are all the places the other 2 sides of the triangle could end.
Notice that these 2 circles do not intersect.
Therefore there can be no triangle 5, 5, 11
2006-10-13 08:45:26 · answer #2 · answered by yupchagee 7 · 0⤊ 0⤋
In order to form a triangle, the 2 sides of the triangle added together should be larger than the third. that is true for all except for a). A is false because 5 + 5 < 11
2006-10-10 07:44:15 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Remember that the sum of any two sides has to be greater than the third side. I usually add the two smaller numbers to see if that sum is greater than the largest number. Example: 2,2,5 would not be a triangle because 2 + 2 is not greater than 5. Now, two of these problems would not form a triangle - can you pick them out? Good luck!
2006-10-10 07:45:19 · answer #4 · answered by tlf 3 · 0⤊ 0⤋
Each side must be less than the sum of the other two sides. Take each side length, and compare it to the sum of the other two. If it is greater than that sum, it can't be a triangle.
Based on that criterion, two of these triangles are impossible.
2006-10-10 07:44:25 · answer #5 · answered by James L 5 · 0⤊ 0⤋
c) can not be correct
The reason? The two shortest sides must at least equal the length of the longest side, otherwise they cannot be connected point to point. 4 + 3 < 8. The side 8 units long just can't be connected to the endpoints of the other two sides.
2006-10-10 07:46:16 · answer #6 · answered by Draco Moonbeam 3 · 0⤊ 0⤋
first of all this is asking for the pathagorean triple that would work in a2+b2=c2
next plug in all the numbers the way they are:
a) 5 squared+five squared equals 11 squared
u put the 5 squared +5 squared in the calculator and see if that comes out to 11 squared
now u know that 11 squared is not 50 so that is not the answer!
after that u try the other choices
the one thats impossible is all of them. none of them come out right , i dont kno if u copied the problem right!
2006-10-10 08:13:12 · answer #7 · answered by Anonymous · 0⤊ 0⤋
a) and c) do not
The sums of two sides cannot be less than the 3rd side
for a) 5+5 < 11
for c) 4 +3 < 8
2006-10-10 07:54:26 · answer #8 · answered by Steve P 5 · 0⤊ 1⤋
a
Any 2 lengths cannot be equal to or smaller than the other length.
2006-10-10 07:44:34 · answer #9 · answered by Anonymous · 0⤊ 1⤋