my co-worker posed this problem to me.... she can't seem to solve it (and I dont remember how to solve it. We have the answer, which is 35....its for GMAT Prep...PLEASE ANSWER IN THE SIMPLEST FORM
2006-10-10 07:35:07 · 4 answers · asked by Tamika H 1 in Science & Mathematics ➔ Mathematics
The answer cannot be 35. The right side of the equation equals 500. Raising fractions to powers reduces their value. Are you sure you copied it right.
2006-10-10 07:43:21 · answer #1 · answered by davidosterberg1 6 · 0⤊ 0⤋
The solution to the problem is as below:
(1/4)^m * (1/5)^18 = 1/2(10)^3
4^-m * 5^-18 = 2^-1 (2^3*5^3)
4^-m *5^-18 = 2^2 *5^3
2^-2m *5^-18 = 2^2*5^3
(2^ -2m)/2^2 = (5^3)/5^-18
(2^-2m)*(2^-2) = 5^3*5^18
2^(-2m-2) = 5^21
(-2m-2)log2 = 21log5
(-2m-2)*0.3010 = 21*0.6990
(-2m-2) = 14.679/0.3010
(-2m -2) = 48.76
(-2m) = 50.76
m = - 25.38
Since the answer does not match your answer of 35, however I believe I've tried given you a hint as you've mentioned that you have forgotten how to solve.
Sorry, tried my luck, didnt seem to be working
2006-10-10 15:14:33 · answer #2 · answered by rouhi a 1 · 0⤊ 0⤋
I agree. Either the problem or the answer is misstated:
-mln4=ln500+18ln5
m = -(ln500+18ln5)/ln4
m = -5.643856
2006-10-10 15:24:18 · answer #3 · answered by Helmut 7 · 0⤊ 0⤋
You will find sol'n here:
http://answers.yahoo.com/question/index;_ylt=Aj_79NjEO0083GUf345WV0Tzy6IX?qid=20061010105730AAfHTDO
2006-10-10 14:38:54 · answer #4 · answered by jacinablackbox 4 · 0⤊ 0⤋