2006-10-10 07:13:16 · 15 answers · asked by pepsicola 2 in Entertainment & Music ➔ Television
Yes I did - I say, yes I did!
2006-10-10 07:15:59 · answer #1 · answered by Talk To The Hand 2 · 0⤊ 0⤋
Why? would can cry at corrie last night.
2006-10-10 07:14:57 · answer #2 · answered by justmejimw 7 · 0⤊ 0⤋
i presumed it became completed properly and detrimental Maria going it on my own thank goodness Sean's boyfriend became there for her. Having experienced this style of beginning as a nurse it is between the main confusing circumstances and it is an extremely quiet element in simple terms like the way they portrayed the silence is deafning.
2016-11-27 19:30:40 · answer #3 · answered by meriwether 4 · 0⤊ 0⤋
I was so sad! i didnt even know he was going. i was really shocked. poor audrey and bev and ashley. i will miss fred in corrie. i say i will miss him and his scotch and threat (what was that by the way) :(
2006-10-10 07:38:12 · answer #4 · answered by jellybean 4 · 0⤊ 0⤋
Oh god i did. I couldn't help it and i know its not real but Audreys tear streaked face and poor Bev trying to picture his last moments was just too much for me, I was lost in it.....Audrey and Bev acted it out so well and Fred.....and yes so did our Ashley......boo hoo......I said so did our Ashley
2006-10-10 07:18:55 · answer #5 · answered by chris w. 7 · 1⤊ 0⤋
Cry, I cry every time I see it, but ,then again, not as much as when I see the acting in East eanders!!!!!
2006-10-10 11:01:02 · answer #6 · answered by Anonymous · 0⤊ 0⤋
I did
The moment the wife said I had to watch it i cried
2006-10-10 07:22:10 · answer #7 · answered by pop 4 · 0⤊ 0⤋
yes i did i thought it was one of the most moving episodes i have ever watched what a sad person i am
2006-10-10 07:30:30 · answer #8 · answered by Anonymous · 0⤊ 0⤋
yes because my misses made me watch both episodes
2006-10-10 07:25:02 · answer #9 · answered by headscab 1 · 0⤊ 0⤋
i cried when albert tatlock died,but ussually i just cry from laughing.
2006-10-10 07:22:00 · answer #10 · answered by Anonymous · 0⤊ 0⤋