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2 Mg(s) + O2(g) 2 MgO(s) H = -1204 kJ

2006-10-10 07:08:22 · 1 answers · asked by Anonymous in Education & Reference Homework Help

1 answers

If the reaction 2 Mg(s) + O2(g) -> 2 MgO(s) has an enthalpy of -1204kJ, then the enthalpy is -602 kJ/mol of MgO.

Step 1: Find the molar mass.
MgO has a molar mass of 24.3 + 16 = 40.3 g/mol

Step 2: Convert kJ/mol to kJ/g
-602 kJ/mol / 40.3 g/mol = -14.938 kJ/g

Step 3: Use the equation: H = H/g * m to find the mass.
-96 kJ = -14.938 kJ/g * x g
x = -96 / -14.938 = 6.42 g MgO

2006-10-12 04:59:32 · answer #1 · answered by ³√carthagebrujah 6 · 0 0

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