This has been asked many times and ans is 2520
this is LCM of all numbers from 1 to 10
2,3,4,5 are facto of numbers 6 to 10 some one
we need to compute
LCM 6,7,8,9,10
= 7*LCM(6,8,9,10)
= 7*40*9 taking higest powers = 2520
2006-10-10 04:51:52
·
answer #1
·
answered by Mein Hoon Na 7
·
3⤊
0⤋
2520 is the smallest number which is the multiple of all the numbers from 1 to 10 [ both inclusive ).
(1=1*1
2=2*1
3=3*1
4=2*2*1
5=5*1
6=2*3*1
7=7*1
8=2*2*2*1
9=3*3*1
10=2*5*1
Now, LEAST COMMON MULTIPLIER
=1*2*2*2*3*3*5*7
=2520.)
2006-10-10 12:02:37
·
answer #2
·
answered by Anonymous
·
2⤊
0⤋
Its the LCM
LCM of all powers of 2 less than 10 =8
LCm of all powers of 3 less than 10 =9
Then it is 5
6 already accounted for in 2 and 3
Next is 7
10 already accounted in 2 and 5
so LCM = 8X9X5 X7 = 2520 Ans
2006-10-10 13:55:12
·
answer #3
·
answered by Stellar K 1
·
1⤊
0⤋
2520
1 * 2 * 3 * 2 * 5 * 7 * 2 * 3
using any combination of the digits above, all of the whole nubmers from 1-10 can be defined with either the number itslef, or with multiplication. Nothing is omitted, nothing is unnecessary.
There are several answers that return this - the correct answer. Anyone rating this or a similar answer thumbs-down needs to review their mathematics, or check their pride.
2006-10-10 11:54:56
·
answer #4
·
answered by Anonymous
·
1⤊
1⤋
i believe you mean the least common multiple of all integers from 1 to 10:
1*2*2*2*3*3*5*7=2520
8 = 2*2*2 (includes 2 and 4 and used for 6 and 10)
9 = 3*3 (includes 3 and used for 6)
5 (used for 10)
7
you will see that all of the numbers have been accounted for.
2006-10-10 11:47:16
·
answer #5
·
answered by jimvalentinojr 6
·
6⤊
1⤋
It is called ten factorial and written 10!
2006-10-10 11:47:28
·
answer #6
·
answered by Rich Z 7
·
1⤊
7⤋
its simply10! or"10 factorial"
2006-10-10 11:50:23
·
answer #7
·
answered by Anonymous
·
1⤊
6⤋
2520..what was that..its actually L.C.M of factorial of 10!
2006-10-10 11:50:07
·
answer #8
·
answered by abusahabuddin 2
·
1⤊
6⤋
181440
2006-10-10 11:54:32
·
answer #9
·
answered by arunjp1989 1
·
0⤊
3⤋