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9 answers

This has been asked many times and ans is 2520
this is LCM of all numbers from 1 to 10
2,3,4,5 are facto of numbers 6 to 10 some one
we need to compute
LCM 6,7,8,9,10
= 7*LCM(6,8,9,10)
= 7*40*9 taking higest powers = 2520

2006-10-10 04:51:52 · answer #1 · answered by Mein Hoon Na 7 · 3 0

2520 is the smallest number which is the multiple of all the numbers from 1 to 10 [ both inclusive ).

(1=1*1
2=2*1
3=3*1
4=2*2*1
5=5*1
6=2*3*1
7=7*1
8=2*2*2*1
9=3*3*1
10=2*5*1
Now, LEAST COMMON MULTIPLIER
=1*2*2*2*3*3*5*7
=2520.)

2006-10-10 12:02:37 · answer #2 · answered by Anonymous · 2 0

Its the LCM
LCM of all powers of 2 less than 10 =8
LCm of all powers of 3 less than 10 =9
Then it is 5
6 already accounted for in 2 and 3
Next is 7
10 already accounted in 2 and 5
so LCM = 8X9X5 X7 = 2520 Ans

2006-10-10 13:55:12 · answer #3 · answered by Stellar K 1 · 1 0

2520

1 * 2 * 3 * 2 * 5 * 7 * 2 * 3

using any combination of the digits above, all of the whole nubmers from 1-10 can be defined with either the number itslef, or with multiplication. Nothing is omitted, nothing is unnecessary.

There are several answers that return this - the correct answer. Anyone rating this or a similar answer thumbs-down needs to review their mathematics, or check their pride.

2006-10-10 11:54:56 · answer #4 · answered by Anonymous · 1 1

i believe you mean the least common multiple of all integers from 1 to 10:

1*2*2*2*3*3*5*7=2520

8 = 2*2*2 (includes 2 and 4 and used for 6 and 10)
9 = 3*3 (includes 3 and used for 6)
5 (used for 10)
7

you will see that all of the numbers have been accounted for.

2006-10-10 11:47:16 · answer #5 · answered by jimvalentinojr 6 · 6 1

It is called ten factorial and written 10!

2006-10-10 11:47:28 · answer #6 · answered by Rich Z 7 · 1 7

its simply10! or"10 factorial"

2006-10-10 11:50:23 · answer #7 · answered by Anonymous · 1 6

2520..what was that..its actually L.C.M of factorial of 10!

2006-10-10 11:50:07 · answer #8 · answered by abusahabuddin 2 · 1 6

181440

2006-10-10 11:54:32 · answer #9 · answered by arunjp1989 1 · 0 3

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