prove that 1+1=1...?

Question

remember that...

c^2 = a^2 + b^2

a^2 = c^2 - b^2

b^2 = c^2 - a^2


who can prove this...
i will choose and give five pts the correct answer...

i know the answer... believe me....

Answer 1

There is no such thing as valid proof of 1 + 1 = 2
There are however tricks that make it sound valid, but arn't

By the way how can the pythagrian therem be used in this proof this only applies to right triangles it can not be used as a general a, b, and c variable.

Answer 2

i can prove the answer is no.

practical reasoning alone proves it wrong.

in the realm of theoretical mathematics it may exist..

but it does not help the real world.

one raise to any power is equal to one.

you gave the phytagorean a^2+b^2=c^2, so if a & b is 1 then c=squareroot of 2 which is an irrational number.

how come you link it up to 1+1=1?

does not matter.. but 1+1=1 is proven wrong by merely practical reasoning. anywhere in the universe 1+1 will always equals 2, the symbols may differ.. but the universallity of it holds true forever..

goodnight! (",)

Answer 3

a and b are real numbers and a=b.
a=b (given)
a^2=ab (multiply by a)
a^2-b^2=ab-b^2 (subtract b^2)
(a+b)(a-b)=b(a-b) (factor out a-b)
a+b=b (divide by a-b, you cannot do this because this leads to 0/0, which is undefined)
a+a=a (substitute a for b)
1+1=1 (divide by a)

Answer 4

Hi,
it's impossible to prove that 1+ 1 = 1.
In the proof you have to divide by zero. You can't divide by zero therefore the proof is unsound.

:-)

Answer 5

ill leave out your little hint,
start with this.... A = B

------------------ *A

A^2 = AB

-------------------- +(A^2 - 2AB)

2A^2 - 2AB = A^2 - AB

-------------- {simplify}

2(A*2 - AB) = A*2 - AB

-------------------- devide by A*2 - AB

2 = 1

if 2 = 1 then 1+1 = 2 = 1
1+1 is also equal to 4, as 1 + 1 = 2 + 2

Answer 6

your maths it pretty shite if you choose best answer surely its gotta be 10 points?

Answer 7

Arrgghhh!!!!
I hate sums...