For your third term, do you mean 2/3 times x or 2 over 3x? It's unclear, and depending on what you meant you will get two different answers.
I'm going to assume you meant 2/3 times x {which should be written as (2/3)x} and will solve for this.
In general, when solving problems of this type you want to get all your x terms on one side and all your constants on the other side, so you can solve for the value of x.
6x - 1/5 = (2/3)x + 7/5
6x - (2/3)x = 7/5 + 1/5
(16/3)x = 8/5
16x = 24/5
x = 24/(16*5) = 3/10
2006-10-10 02:34:40
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answer #1
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answered by I ♥ AUG 6
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6x - 1/5 = 2/3x + 7/5 add 1/5 to both sides
6x-1/5+1/5 = 2/3x +7/5 + 1/5
6x = 2/3x + 8/5 subtract 2/3x from both sides
6x - 2/3x = 2/3x - 2/3x + 8/5
16/3x = 8/5 multiply by 3/16 on both sides to get x isolated
(3/16)(16/3x) = (3/16)(8/5)
x = 3/10
Hope this helps. Good Luck.
2006-10-10 09:33:34
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answer #2
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answered by SmileyGirl 4
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6x - 1/5 = 2/3x + 7/5
1) add 1/5 to both sides
6x - 1/5 + 1/5 = 2/3x + 7/5 + 1/5
6x = 2/3x + 8/5
2) subtract 2/3x from both sides
6x - 2/3x = 8/5
18/3x - 2/3x = 8/5
16/3x = 8/5
3) multiply both sides by 3/16
3/16(16/3)x = 3/16(8/5)
x=24/80
4) reduce by 8
x= 3/10
2006-10-10 09:33:53
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answer #3
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answered by ezgoin92 5
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6x - 1/5= 2/3x +7/5 subtract 2/3x from both sides
5 1/3 x -1/5=7/5 add 1/5 to both sides
5 1/3 x=8/5 5 1/3= 16/3 divive throught by 16/3
x= (8/5)/(16/3)=(1/5)/(2/3)=1/5 x 3/2=3/10
3/10
http://www.khake.com/page47
2006-10-10 09:42:18
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answer #4
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answered by Anonymous
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Multiply through out by 15.You will get rid of fractions. Then collect terms containg x on the left and pure numbers on the right.Solve to get x.
2006-10-10 09:39:38
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answer #5
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answered by Rajesh Kochhar 6
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uve got me confused
2006-10-10 09:28:36
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answer #6
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answered by sparkynicci 3
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