2006-10-09 16:36:18 · 5 answers · asked by elan t 1 in Science & Mathematics ➔ Mathematics
x= 72-(16+x^2) - (16-rx^2)/U
2006-10-09 16:48:06 · answer #1 · answered by David S 2 · 0⤊ 0⤋
U(x) = 72 - (4 + x)^2 - (4 - rx)^2
U(x) = 72 - ((4 + x)(4 + x)) - ((4 - rx)(4 - rx))
U(x) = 72 - (16 + 4x + 4x + x^2) - (16 - 4rx - 4rx + (rx)^2)
U(x) = 72 - (16 - 8x + x^2) - (16 - 8rx + (rx)^2)
U(x) = 72 - 16 + 8x - x^2 - 16 + 8rx - (rx)^2
U(x) = (-r - 1)x^2 + (8 + 8)x + (72 - 16 - 16)
U(x) = -(r + 1)x^2 + 16x + 32
assuming you didn't mistype anything
x = (-b ± sqrt(b^2 - 4ac))/(2a)
x = (-16 ± sqrt(16^2 - 4(-(r + 1))(32))/(2(-(r + 1)))
x = (-16 ± sqrt(256 + 128(r + 1)))/(-2(r + 1))
x = (-16 ± sqrt(128(2 + (r + 1))))/(-2(r + 1))
x = (-16 ± sqrt(64(2(2 + r + 1)))))/(-2(r + 1))
x = (-16 ± 8sqrt(2(2 + r + 1)))/(-2(r + 1))
x = (8 ± 4sqrt(4 + 2(r + 1)))/(r + 1)
ANS : (1/(r + 1))(8 ± 4sqrt(4 + 2(r + 1)))
2006-10-10 00:04:35 · answer #2 · answered by Sherman81 6 · 0⤊ 0⤋
U(x) = 72 - 16 -8x - x^2 - 16 + 8rx - r^2x^2
(r^2+1)x^2 - (r-1)x -50-U = 0
x = (r-1)±sqrt((r-1)^2 + 4(r^2+1)(50-U))/2/(r^2+1)
2006-10-09 23:54:42 · answer #3 · answered by Helmut 7 · 0⤊ 0⤋
x = 40 -8x-x^2 +8rx-rx^2/ U
2006-10-10 00:16:47 · answer #4 · answered by Freesia 5 · 0⤊ 0⤋
r no longer equals "constance"?
2006-10-09 23:43:30 · answer #5 · answered by geek49203 6 · 0⤊ 1⤋