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You decide to drive around a circular track of radius 50.0 m in your car starting from rest. You accelerate with a constant tangential acceleration of 2.00 m/s2. You are initially at the far west side of the circular track and will travel counter clock-wise.
(a) What is the speed of your car when you have traveled ¼ the circumference of the track?
(b) At that point, what is the centripetal acceleration of your car?
(c) At the same point, what is the total acceleration?

2006-10-09 16:17:22 · 1 answers · asked by James B 1 in Science & Mathematics Physics

1 answers

s = 25pi
a)
v^2 = 2*2*25*pi m/s, ( = 2as, starting from rest)
b)
(v^2)/r = 2*2*25*pi/50 = 2pi m/s/s
c)
a = sqrt(4 + 4pi^2 +9.8^2) m/s/s

2006-10-09 16:35:01 · answer #1 · answered by Helmut 7 · 0 0

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