the length of a rectangular garden is 3yd more than twice its width. the perimeter of the garden is 36yd. what are the width and length of the garden
2006-10-09 16:03:09 · 4 answers · asked by Raul X 1 in Education & Reference ➔ Homework Help
L = 2W + 3
P = 2L + 2W
= 2(2W+3) + 2W
= 4W + 6 + 2W
= 6W + 6
6W + 6 = 36
6W = 30
W = 5
L = 2W+3 = 13
Now check your work:
"The length of a rectangular garden is 3yd more than twice its width." Yep. Width = 5. Twice width = 10. 3 more is 13.
"The perimeter is 36yd." Yep. 13 + 5 + 13 + 5 = 36.
2006-10-09 16:06:28 · answer #1 · answered by PJ 3 · 0⤊ 0⤋
call the width of that garden x.
so the length is: 2x +3
The parameters is 36 yd
so 2* [ x + ( 2x+3) ] =36
=> 2 * ( 3x +3 ) =36
=> x =5 yd.
so : the width is 5 yds, the length is 13 yds
2006-10-09 23:08:48 · answer #2 · answered by Anonymous · 0⤊ 0⤋
call the width of that garden x.
so the length is: 2x +3
The parameters is 36 yd
so 2* [ x + ( 2x+3) ] =36
=> 2 * ( 3x +3 ) =36
=> x =5 yd.
so : the width is 5 yds, the length is 13 yds.
2006-10-09 23:07:48 · answer #3 · answered by hoang_hiepsi 4 · 0⤊ 0⤋
i aint helping you on your homework
2006-10-09 23:06:43 · answer #4 · answered by iMegan 3 · 0⤊ 0⤋