need your help please...thanks?

Question

true or false......
is a parabola is a function?
h(x)= x - 1, the domain x can't be 0 and 1?
y = x^2 - 5 is a linear equation
3x + 2y = 6 has intercept form of (2,0)
y = -4 has undefined slope
slope of 2x - y = 2
the domain of y = 2x + 6 is cannot be -3
the graph of letter z is a function



write an equation of a line perpendicular to line
y = 3x - 1and going through point ( -9,1 )


solve.
f(x) =4x + 5
g(x) =2x - 1
h(x)= x^2


a. f(g(-3))=

b.g(x)=27 find x

c. g(f(x))





please show me how you did it thanks a lot.......:)

Answer 1

Have you given any consideration to not asking this many questions at once? I'll give you the first couple.

Is a parabola a function? Yes. Consider the graph - a parabola passes the vertical line test.

h(x) = x - 1, the domain can't include 0 or 1. False. The domain includes any values not specifically restricted for which you can obtain a sensible answer. If I plug in 0 for x, I get -1: no problem. If I plug in 1 for x, I get 0: again, no problem.

y = x^2 - 5 is a linear function. False. Linear function will have no powers on the variables higher than 1. This function is quadratic in x, so non-linear. In fact, it's a parabola.

3x + 2y = 6 has intercept form of (2,0) The question is badly worded, and I'm not sure what it means. There are several possible "intercept" forms for the equation of a line - what you have here is not one of them. I presume the question is asking if the x-intercept of this line is (2, 0). Just plug in the values:

3(2) + 2(0) = 6, which works. So, if I've interpreted the question correctly, this is true.

y = -4 has undefined slope. False. y=-4 is a horizontal line, which has a slope of 0. If the question were "x = -4 has undefined slope", that would be true. Vertical lines have undefined slope.

That should get you started, at least. One suggestion: learn the vocabulary. Most of these questions are really well-disguised vocabulary questions.

Answer 2

Jenn,

I will answer 3 questions only. What sense is there for another person to do what appears to be your homework? Am I going to be in class with you? No. You need not post so many questions because no one will do your homework.

1. Is a parabola a function?

Answer: The graph of a quadratic function is called a parabola.
So, the answer is yes. The parabola is a type of function called quadratic function.

2. For h(x)= x - 1, the domain x can't be 0 and 1? In this case, the domain can be any number that you plug in for x. Now, if x was a denominator, then x could not be zero. However, in your question, x can = 0 and/or 1.

3. Is y = x^2 - 5 a linear equation. The answer is no. Why? Do you see the x^2? Everytime you you a square or any other exponent greater than 1 in a given equation, you are no longer dealing with a linear equation. The word linear comes from the word LINE. A linear equation means A STRAIGHT LINE.
The equation y = x^2 - 5 is another parabola, which is not linear.

Now, you do the rest.

Guido

Answer 3

parabola is a function
false, x CAN be 0 and/or 1
y=x^2-5 is a parabola....linear equation describes a line
3x+2y=6 equals y=-(3/2)x+3
y=-4 is a horizontal line, with a slope of zero....undefined slope has to be a vertical line
2x-y=2 equals y=2x-2, yes its slope is (2/1)
the domain can be -3...the only way a domain is not defined is when x is in the denominator and the denominator cant equal zero OR x is in a square root
no the graph of letter z is not a function because it does not pass the vertical line test

y=3x-1 (-9,1)
perpendicular line has a negative reciprical slope of original equation
y=3x-1
slope:3
perpendicular slope: -(1/3)
y=-(1/3)x+b
plug in the point (-9,1)
1=-(1/3)(-9)+b
1=3+b
b=-2
final equation:
y=-(1/3)x - 2

do the rest ur self....

Answer 4

Oh god did you save your homework til the night before on a long weekend?!?! Sorry I have no idea.


Somebody help the girl!

Answer 5

it's all going over my head, sorry

Answer 6

oh my...i totally forgot evrything!!!!!!