Factor 64x(cubed) - 125?

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Factor 64x(cubed) - 125?

kthx.

2006-10-09 15:16:50 · 4 answers · asked by somerandomdude2006 1 in Science & Mathematics ➔ Mathematics

4 answers

Ok lets break this down

64x(cubed) - 125
= (4x)^3 + (-5)^3 ( Now its in the form A^3 + B^3 )
= (4x-5)(16x^2 + 20x + 25 )

We have used the formula
A^3 + B^3 = (A + B)(A^2 + AB + B^2)

2006-10-09 15:39:44 · answer #1 · answered by The Zing Thing 1 · 0⤊ 0⤋

64x^3 - 125 = (4x - 5)(16x^2 + 20x + 25)

2006-10-10 00:34:18 · answer #2 · answered by Sherman81 6 · 0⤊ 0⤋

64x^3-125
= (4x-5) (16x^2+20x+25)

2006-10-09 22:24:29 · answer #3 · answered by hi 1 · 0⤊ 0⤋

This one is tricky. I think the answer is (4x-5)(16x^2 + 20x + 25). The quadratic can only be factored with imaginary numbers

2006-10-09 22:25:31 · answer #4 · answered by Anonymous · 0⤊ 0⤋