2006-10-09 13:54:14 · 17 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
121
It looks like a sequence of the squares of primes.
So, we have 1^2, 2^2, 3^2, 5^2, 7^2, 11^2.
The problem I have is that 1 is not technically a prime number. But it has enough contention that I'm not surprised to see it in that list.
Usually, if you see numbers like those above, then you know you're dealing with squares. Take the square root of each number and examine that sequence.
2006-10-09 13:55:28 · answer #1 · answered by Rev Kev 5 · 1⤊ 0⤋
121. The sequence is related to prime numbers squared. The numbers are 1, 2, 3, 5, 7, 11. 11 squared is 121.
2006-10-09 20:56:11 · answer #2 · answered by robtheman 6 · 2⤊ 0⤋
It is the square of prime numbers after 1 which is why is does not include 16 (square of 4) or 36 (square of 6). The next number is 121 (sqaure of 11) since 8, 9, and 10 arent primes.
2006-10-09 20:57:55 · answer #3 · answered by jackalrama 2 · 1⤊ 0⤋
1, 4, 9, 25, 49, [ 121 ]
It is a sequence of squared powers of primes
1^2, 2^2, 3^2, 5^2, 7^2, 11^2, ...
2006-10-09 21:00:43 · answer #4 · answered by ideaquest 7 · 1⤊ 0⤋
first thing is you are missing 36. the next number would be 64. the pattern is 1*1=1, 2*2=4, 3*3=9...
they are called perfect squares.
2006-10-09 21:10:38 · answer #5 · answered by Dannii™ 3 · 0⤊ 1⤋
121
2006-10-09 21:03:05 · answer #6 · answered by CAC777 2 · 0⤊ 0⤋
121, the numbers are the prime values from 1-7 and each of them is squared
2006-10-09 20:56:23 · answer #7 · answered by Just another 2D character online 3 · 1⤊ 1⤋
121. I thought 1 was considered prime.
2006-10-09 20:56:08 · answer #8 · answered by campbelp2002 7 · 0⤊ 1⤋
64
2006-10-09 20:55:49 · answer #9 · answered by lfheslin 2 · 0⤊ 2⤋
What happened to 36?
2006-10-09 20:55:39 · answer #10 · answered by Anonymous · 0⤊ 1⤋