2006-10-09 13:40:36 · 8 answers · asked by Spyduh Munkee 1 in Education & Reference ➔ Homework Help
Well, half of all the 3 digit numbers would be odd, right? Since numbers alternate between odd and even.
So how many positive 3-digit numbers are there? Well, that's just all the numbers between 100 and 999, which is 900 numbers.
Therefore, 450 are odd (and 450 are even).
I hope this explanation helps you see how you can reason these out for yourself.
2006-10-09 13:44:10 · answer #1 · answered by I ♥ AUG 6 · 0⤊ 2⤋
There are 899 positive 3 digit numbers.
There are 499 positive 4 digit numbers ALONE with just "1" as the first digit. So there are 998 with "1" or "2" as the first digit. That's all you need.
2006-10-09 13:54:31 · answer #2 · answered by Anonymous · 0⤊ 2⤋
three digit numbers are 100 - 999 inclusive so there are 999-100+1 three digit numbers in total..... so that is 900 three digit numbers....
if half of all numbers is odd then half of 900 is 450, there are 450 odd positive 3 digit numbers....
2006-10-09 13:46:10 · answer #3 · answered by ed-dg 2 · 0⤊ 1⤋
450
2006-10-09 13:44:34 · answer #4 · answered by dtaschan 2 · 0⤊ 2⤋
You figure there are numbers 100 to 999
that is 899 numbers
divide that by two and you have that many odd numbers
divide that by two and you have that many odd numbers
I say there is 449.5 odd 3 digit odd numbers
2006-10-09 13:47:29 · answer #5 · answered by Jeremiah H 1 · 1⤊ 3⤋
45
2006-10-09 13:43:36 · answer #6 · answered by Anonymous · 0⤊ 2⤋
450
2006-10-09 13:45:06 · answer #7 · answered by Irish Eyes 4 · 0⤊ 2⤋
two
2006-10-09 13:42:06 · answer #8 · answered by Anonymous · 0⤊ 3⤋