A metal object with a mass of 19g is heated to 96C (degrees centigrade), then transferred to a calorimeter containing 75g of water at 18C. The water and metal object reach a final temperature of 22C.
a)What is the specific heat of the metal in cal/gC and in J/gC?
b) What is the metal?
I have this question on my study guide and it's not a turn in question for chemistry. The formula for specific heat is
Specific Heat (SH=heat/mass x difference temperature)
2006-10-09 13:22:43 · 2 answers · asked by MzzandtheChuchuBees 5 in Science & Mathematics ➔ Chemistry
HEAT GAINED BY THE WATER:
Q1=75(1)(22-18) THE SPECIFIC HEAT OF WATER IS 1 CAL/g ºc
Q1= 300 cal
HEAT LOST BY THE METAL:
Q2=19 SH(96-22),
Q1=Q2
300=19 SH(74), SO SH=0.2134 CAL/g ºc
metal maybe aluminium (sorry my english)
2006-10-09 14:08:29 · answer #1 · answered by Carlos T 4 · 1⤊ 0⤋
For water Heatw = mw * cpw * DeltaTw
The same heat[metal] = Heat[water]
so Cp[metal] = Heat/mass[metal]/DeltaTm
Go to a Cp table and look what metal has you Cp.
2006-10-09 20:31:40 · answer #2 · answered by Dr. J. 6 · 0⤊ 0⤋