Write an equation of the line containing the speified point and perpindicular to the indicated line.
y=2x-2
slop of the perp = 1/2
y+5 = 1/2(x-3)
y=1/2x + 7/2
Is this right?
2006-10-09 13:13:50 · 4 answers · asked by born2bfree 3 in Education & Reference ➔ Homework Help
The indicated line has slope 2, so the perpendicular line, whose equation you're finding, has slope -1/2 (the negative of the reciprocal).
y+5 = (-1/2)(x+3)
y+5 = (-1/2)x - 3/2
y = (-1/2)x - 13/2
2006-10-09 13:39:05 · answer #1 · answered by Consider This... 3 · 0⤊ 0⤋
You're not changing the sign on the slope. It should be negative. If you think about perpendicular lines, they slant different ways, so one will have a positive slope and the other will be negative. So in your equation, make the 1/2 negative. You also have to make the 3 in the parentheses positive. Then you'll be OK
2006-10-09 13:17:57 · answer #2 · answered by PatsyBee 4 · 0⤊ 0⤋
ok. i'm no longer doing them involved approximately you, yet i will prepare you an occasion. For the 1st one, distribute the three to get 6y-12=9. Get y on my own (aka upload 12) you will finally end up with 6y=21 Divide by 6 and your answer is y=7/2. For the others, do the comparable element. For the places the place you have 2 words with a variable, use FOIL and then sparkling up for x utilising the procedures from the occasion I did. for example, 4x+3(20-x) will develop into -4x^2+77x+60, and you'd be able to sparkling up something.
2016-12-26 14:31:37 · answer #3 · answered by ludwig 3 · 0⤊ 0⤋
No, because the slope of a perpendicular line is the OPPOSITE reciprocal of the original slope so it would be -1/2
2006-10-09 13:18:08 · answer #4 · answered by hayharbr 7 · 0⤊ 0⤋