find the length and the width
2006-10-09 13:12:24 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
2(w+5+w)=38
2w+5=19
2w=14
w=7
l=12
length 12cm width=7 cm
2006-10-09 13:15:52 · answer #1 · answered by raj 7 · 0⤊ 0⤋
The formula for the peimeter is
P = 2L + 2 W
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let
w = Width
w = 5 equal length
38 cm equals the perimeter
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P = 2L + 2 W
38 = 2(W + 5 ) + 2W
38 + 2W + 10 + 2W
38 = 4W + 10
38 - 10 = 4W + 10 - 10
28 = 4W
28/4 = 4W/4
7 = W
The answer is W = 7
The solution siet is [ 7 }
Insert the W value into th equation
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Check
P = 2L + 2 W
38 = 2( 7 + 5) + 2( 7)
38 = 2( 12) + 14
38 + 24 + 14
38 = 38
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The length is W + 5
7 + 5 = 12
The Length is 12 cm
2006-10-09 20:36:33 · answer #2 · answered by SAMUEL D 7 · 0⤊ 0⤋
if you draw out a rectangle and label the length x + 5 and label the width x, you have x + 5 + x + 5 + x + x = 38
(because perimeter means to add all of the sides and the opposite sides of a rectangle are equal)
now solve by combining like terms....4x + 10 = 38
subtract 10 from both sides of the =
you now have 4x = 28
divide by 4
x = 7
the width is 7 and the length is 12...
to check add 7 + 7 + 12 + 12 since this equals 38, you got it right!!
2006-10-09 20:18:25 · answer #3 · answered by Tori H 2 · 0⤊ 0⤋
l = w + 5
p = 2(l + w)
38 = 2((w + 5) + w)
38 = 2(w + 5 + w)
38 = 2(2w + 5)
19 = 2w + 5
2w = 14
w = 7
l = 7 + 5 = 12
ANS : Width = 7cm and Length = 12cm
2006-10-09 20:29:46 · answer #4 · answered by Sherman81 6 · 0⤊ 0⤋
l=w+5
p=38cm
p=2w+2l=2w+2(w+5)=4w+10
38=4w+10
4w=28
w=7
l=w+5=12
check
p=2w+2l=2*7+2*12
p=14+24=38
2006-10-13 12:23:51 · answer #5 · answered by yupchagee 7 · 0⤊ 0⤋